Determine the maximum number of electrons that can have each of the following designations: \(2 f, 2 d_{x y}, 3 p, 5 d_{y z},\) and 4\(p .\)

Short Answer

Expert verified
The maximum number of electrons for each designation is: - 2f: 14 electrons - 2d_{xy}: 2 electrons - 3p: 6 electrons - 5d_{yz}: 2 electrons - 4p: 6 electrons

Step by step solution

01

Determine the quantum numbers for each designation

For each designation, let's identify the principal quantum number (n), angular momentum quantum number (l), magnetic quantum number (m_l), and spin quantum number (m_s). 1. 2f: n = 2, l = 3 (since f orbitals correspond to l = 3) 2. 2d_{xy}: n = 2, l = 2 (since d orbitals correspond to l = 2), m_l = -2 (xy refers to the 2nd d orbital) 3. 3p: n = 3, l = 1 (since p orbitals correspond to l = 1) 4. 5d_{yz}: n = 5, l = 2 (since d orbitals correspond to l = 2), m_l = -1 (yz refers to the 3rd d orbital) 5. 4p: n = 4, l = 1 (since p orbitals correspond to l = 1)
02

Apply Pauli Exclusion Principle

According to the Pauli Exclusion Principle, no two electrons in an atom can have the same set of quantum numbers. Since the spin quantum number (m_s) can have only two values (+1/2 and -1/2), at most, two electrons can occupy the same orbital with the same values of n, l, and m_l. To find the maximum number of electrons for each designation, we need to calculate the number of possible m_l values.
03

Calculate the number of possible magnetic quantum numbers

For each designation, let's calculate the number of possible m_l values. Note that for each l value, the range of m_l values is -l, -(l-1), ..., 0, ...., (l-1), l. 1. 2f: For l = 3, m_l values range from -3 to 3. There are a total of 7 possible m_l values. 2. 2d_{xy}: For l = 2 and m_l = -2, there's only one possible m_l value. 3. 3p: For l = 1, m_l values range from -1 to 1. There are a total of 3 possible m_l values. 4. 5d_{yz}: For l = 2 and m_l = -1, there's only one possible m_l value. 5. 4p: For l = 1, m_l values range from -1 to 1. There are a total of 3 possible m_l values.
04

Apply Hund's Rule and calculate the maximum number of electrons

According to Hund's Rule, electrons will fill the orbitals in such a way that they maintain the maximum possible multiplicity (maximum number of unpaired electrons). So, the maximum number of electrons for each designation can be determined by multiplying the number of m_l values by 2 (for the two possible spin quantum numbers, +1/2 and -1/2). 1. 2f: Maximum electrons = 7 m_l values * 2 spins = 14 2. 2d_{xy}: Maximum electrons = 1 m_l value * 2 spins = 2 3. 3p: Maximum electrons = 3 m_l values * 2 spins = 6 4. 5d_{yz}: Maximum electrons = 1 m_l value * 2 spins = 2 5. 4p: Maximum electrons = 3 m_l values * 2 spins = 6 In conclusion, the maximum number of electrons for each designation is as follows: - 2f: 14 electrons - 2d_{xy}: 2 electrons - 3p: 6 electrons - 5d_{yz}: 2 electrons - 4p: 6 electrons

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