Write the expected ground-state electron configuration for the following: a. the element with one unpaired 5\(p\) electron that forms a covalent with compound fluorine b. the (as yet undiscovered) alkaline earth metal after radium c. the noble gas with electrons occupying 4f orbitals d. the first-row transition metal with the most unpaired electrons

Short Answer

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a. Antimony (Sb) electron configuration: \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^3\] b. Unbinilium (Ubn) electron configuration: \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 4f^{14} 5d^{10} 6p^6 7s^2\] c. Radon (Rn) electron configuration: \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 4f^{14} 5d^{10} 6p^6\] d. Chromium (Cr) electron configuration: \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^1 3d^5\]

Step by step solution

01

a. Element with one unpaired 5\(p\) electron that forms a covalent with compound fluorine

First, we need to find the element with one unpaired 5\(p\) electron. In the periodic table, this element is in the 5th period and the 15th group (Elements with \(n=5\) in a \(p\) orbital). That element is antimony (Sb). Now, let's find the ground-state electron configuration for antimony: 1. Utilizing the aufbau principle, we have: \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^3\] 2. Final electron configuration of antimony (Sb): \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^3\]
02

b. Alkaline earth metal after radium

To find the alkaline earth metal after radium, we need to move one element down in the 2nd group of the periodic table. The element we are looking for is element 120, which has not been discovered yet. This element is known as unbinilium (Ubn). Now, let's find the ground-state electron configuration for unbinilium (Ubn): \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 4f^{14} 5d^{10} 6p^6 7s^2\] Final electron configuration of unbinilium (Ubn): \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 4f^{14} 5d^{10} 6p^6 7s^2\]
03

c. Noble gas with electrons occupying 4f orbitals

Noble gases have completely filled electron shells. We are looking for a noble gas with electrons occupying 4f orbitals. In the periodic table, we see that radon (Rn) is the noble gas element where the 4f orbitals are completely filled. Now, let's find the ground-state electron configuration for radon (Rn): \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 4f^{14} 5d^{10} 6p^6\] Final electron configuration of radon (Rn): \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 4f^{14} 5d^{10} 6p^6\]
04

d. First-row transition metal with the most unpaired electrons

First-row transition metals are found in the 4th period and groups 3 to 12. The first-row transition metal with the most unpaired electrons is chromium (Cr). Now, let's find the ground-state electron configuration for chromium (Cr): 1. Utilizing the aufbau principle, we have: \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^1 3d^5\] 2. Chromium has an exception to the aufbau principle because half-filled d orbitals are more stable, so it promotes one electron from the 4s orbital to the 3d orbital. Final electron configuration of chromium (Cr): \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^1 3d^5\]

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