In the ground state of mercury, Hg, a. how many electrons occupy atomic orbitals with \(n=3 ?\) b. how many electrons occupy \(d\) atomic orbitals? c. how many electrons occupy \(p_{z}\) atomic orbitals? d. how many electrons have spin "up" " \(\left(m_{s}=+\frac{1}{2}\right) ?\)

Short Answer

Expert verified
In the ground state of mercury: a. 18 electrons occupy atomic orbitals with n=3. b. 20 electrons occupy d atomic orbitals. c. 8 electrons occupy \(p_{z}\) atomic orbitals. d. 40 electrons have spin "up" with \(m_{s}=+\frac{1}{2}\).

Step by step solution

01

Identify electron configurations with n=3

We're looking at the electron configuration for mercury and finding the configurations with n=3: \(3s^{2}\) \(3p^{6}\) \(3d^{10}\)
02

Add up the number of electrons

In the n=3 orbitals, we have 2 electrons in 3s, 6 electrons in 3p, and 10 electrons in 3d. So the total number of electrons is 2+6+10 = 18 electrons. b. How many electrons occupy d atomic orbitals?
03

Identify electron configurations with d orbitals

In the electron configuration for mercury, we see 3d and 4d orbitals: \(3d^{10}\) \(4d^{10}\)
04

Add up the number of electrons

There are 10 electrons in 3d orbitals and 10 electrons in 4d orbitals. So the total number of electrons in d atomic orbitals is 10+10 = 20 electrons. c. How many electrons occupy \(p_{z}\) atomic orbitals?
05

Identify electron configurations with p orbitals

In the electron configuration for mercury, we see 2p, 3p, 4p, and 5p orbitals: \(2p^{6}\) \(3p^{6}\) \(4p^{6}\) \(5p^{6}\)
06

Determine the number of electrons in \(p_{z}\) orbitals

Each p subshell has three p orbitals (px, py, and pz), and each orbital can hold a maximum of 2 electrons. Thus, there are 2 electrons in every \(p_{z}\) orbital. Since there are four p orbitals with z-component, there are 2*4 = 8 electrons in \(p_{z}\) atomic orbitals. d. How many electrons have spin "up" with \(m_{s}=+\frac{1}{2}\)?
07

Identify all orbitals

We'll use the electron configuration of mercury to list all the occupied orbitals: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d
08

Determine the number of spin-up electrons in each orbital

Every orbital can house 2 electrons (1 spin up and 1 spin down). Therefore, half of the electrons in each orbital are spin up. Similarly, the other half are spin down.
09

Add up the number of spin-up electrons

Mercury has a total of 80 electrons. Half of them will be spin up. So, there are 80/2 = 40 electrons with spin "up" with \(m_{s}=+\frac{1}{2}\).

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