Write Lewis structures and predict the molecular structures of the following. (See Exercises 115 and 116.) a. \(\mathrm{OCl}_{2}, \mathrm{KrF}_{2}, \mathrm{BeH}_{2}, \mathrm{SO}_{2}\) b. \(\mathrm{SO}_{3}, \mathrm{NF}_{3}, \mathrm{IF}_{3}\) c. \(\mathrm{CF}_{4}, \mathrm{SeF}_{4}, \mathrm{KrF}_{4}\) d. \(\mathrm{IF}_{5}, \mathrm{AsF}_{5}\)

Count the number of valence electrons for all atoms in the compound. This will be used to create the Lewis structure.

Place the atoms around the central atom (usually one with the highest valence electron) and connect them with single bonds. Distribute the remaining electrons to fill the octets for each atom.

Count the number of electron groups (bonds and lone pairs) around the central atom and use the VSEPR theory to determine the electron-domain geometry.

Considering the arrangement of the bonding pairs and lone pairs, determine the molecular structure of the compound. Now we will apply these steps to each part of the exercise. a. \(\mathrm{OCl}_{2}, \mathrm{KrF}_{2}, \mathrm{BeH}_{2}, \mathrm{SO}_{2}\) 1. OCl2: 6 (O) + 2 * 7 (Cl) = 20 valence electrons 2. O is the central atom; the Lewis structure is O - Cl - Cl 3. There are 3 electron domains (2 single bonds and 1 lone pair), this indicates a trigonal planar electron-domain geometry 4. The molecular structure is bent, due to the presence of 1 lone pair 1. KrF2: 8 (Kr) + 2 * 7 (F) = 22 valence electrons 2. Kr is the central atom; the Lewis structure is Kr - F - F 3. There are 5 electron domains (2 single bonds and 3 lone pairs), this indicates a trigonal bipyramidal electron-domain geometry 4. The molecular structure is linear, due to the 180° bond angle and the equatorial position of the lone pairs 1. BeH2: 2 (Be) + 2 * 1 (H) = 4 valence electrons 2. Be is the central atom; the Lewis structure is Be - H - H 3. There are 2 electron domains (2 single bonds), this indicates a linear electron-domain geometry 4. The molecular structure is linear 1. SO2: 6 (S) + 2 * 6 (O) = 18 valence electrons 2. S is the central atom; the Lewis structure is S - O = O (with one lone pair on Sulfur) 3. There are 3 electron domains (1 double bond, 1 single bond, and 1 lone pair), this indicates a trigonal planar electron-domain geometry 4. The molecular structure is bent, due to the presence of 1 lone pair b. \(\mathrm{SO}_{3}, \mathrm{NF}_{3}, \mathrm{IF}_{3}\) 1. SO3: 6 (S) + 3 * 6 (O) = 24 valence electrons 2. S is the central atom; the Lewis structure is S(=O)(=O)= O 3. There are 3 electron domains (3 double bonds), this indicates a trigonal planar electron-domain geometry 4. The molecular structure is trigonal planar 1. NF3: 5 (N) + 3 * 7 (F) = 26 valence electrons 2. N is the central atom; the Lewis structure is N - F - F - F (with one lone pair on Nitrogen) 3. There are 4 electron domains (3 single bonds and 1 lone pair), this indicates a tetrahedral electron-domain geometry 4. The molecular structure is trigonal pyramidal, due to the presence of 1 lone pair 1. IF3: 7 (I) + 3 * 7 (F) = 28 valence electrons 2. I is the central atom; the Lewis structure is I - F - F - F (with two lone pairs on Iodine) 3. There are 5 electron domains (3 single bonds and 2 lone pairs), this indicates a trigonal bipyramidal electron-domain geometry 4. The molecular structure is T-shaped, due to the presence of 2 lone pairs in equatorial positions c. \(\mathrm{CF}_{4}, \mathrm{SeF}_{4}, \mathrm{KrF}_{4}\) 1. CF4: 4 (C) + 4 * 7 (F) = 32 valence electrons 2. C is the central atom; the Lewis structure is C - F - F - F - F 3. There are 4 electron domains (4 single bonds), this indicates a tetrahedral electron-domain geometry 4. The molecular structure is tetrahedral 1. SeF4: 6 (Se) + 4 * 7 (F) = 34 valence electrons 2. Se is the central atom; the Lewis structure is Se - F - F - F - F (with one lone pair on Selenium) 3. There are 5 electron domains (4 single bonds and 1 lone pair), this indicates a trigonal bipyramidal electron-domain geometry 4. The molecular structure is seesaw, due to the presence of 1 lone pair 1. KrF4: 8 (Kr) + 4 * 7 (F) = 36 valence electrons 2. Kr is the central atom; the Lewis structure is Kr - F - F - F - F (with two lone pairs on Krypton) 3. There are 6 electron domains (4 single bonds and 2 lone pairs), this indicates an octahedral electron-domain geometry 4. The molecular structure is square planar, due to the presence of 2 lone pairs d. \(\mathrm{IF}_{5}, \mathrm{AsF}_{5}\) 1. IF5: 7 (I) + 5 * 7 (F) = 42 valence electrons 2. I is the central atom; the Lewis structure is I - F - F - F - F - F (with one lone pair on Iodine) 3. There are 6 electron domains (5 single bonds and 1 lone pair), this indicates an octahedral electron-domain geometry 4. The molecular structure is square pyramidal, due to the presence of 1 lone pair 1. AsF5: 5 (As) + 5 * 7 (F) = 40 valence electrons 2. As is the central atom; the Lewis structure is As - F - F - F - F - F 3. There are 5 electron domains (5 single bonds), this indicates a trigonal bipyramidal electron-domain geometry 4. The molecular structure is trigonal bipyramidal