Consider the following energy changes: $$\begin{array}{ll} \text {} & \quad { \Delta H} \\ \text {} & {(k J / m o l)} \\ \hline \\ {\mathrm{Mg}(g) \rightarrow \mathrm{Mg}^{+}(g)+\mathrm{e}^{-}} & {735} \\ {\mathrm{Mg}^{+}(g) \rightarrow \mathrm{Mg}^{2+}(g)+\mathrm{e}^{-}} & {1445} \\ {\mathrm{O}(g)+\mathrm{e}^{-} \rightarrow \mathrm{O}^{-}(g)} & {-141} \\ {\mathrm{O}^{-}(g)+\mathrm{e}^{-} \rightarrow 0^{2-}(g)} & {878}\end{array}$$ Magnesium oxide exists as \(\mathrm{Mg}^{2+} \mathrm{O}^{2-}\) and not as \(\mathrm{Mg}^{+} \mathrm{O}^{-}\) Explain.

Short Answer

Expert verified
The given energy changes for the formation of ions from gaseous elements show that the formation of \(\mathrm{Mg}^{2+} \mathrm{O}^{2-}\) has a total energy change of \(2917 kJ/mol\), while the formation of \(\mathrm{Mg}^{+} \mathrm{O}^{-}\) has a total energy change of \(594 kJ/mol\). Even though both species involve positive energy changes, the formation of \(\mathrm{Mg}^{+} \mathrm{O}^{-}\) is more energetically favorable due to its lower energy change. Nonetheless, magnesium oxide exists as \(\mathrm{Mg}^{2+} \mathrm{O}^{2-}\) rather than \(\mathrm{Mg}^{+} \mathrm{O}^{-}\) as the given energy changes do not account for other factors that may affect stability in real systems.

Step by step solution

01

Identify the energy changes to form Mg2+ and O2-

First, analyze the two given energy changes required to create \(\mathrm{Mg}^{2+}\) and \(\mathrm{O}^{2-}\) ions. For \(\mathrm{Mg}^{2+}\) 1. \(\mathrm{Mg}(g) \rightarrow \mathrm{Mg}^{+}(g) + \mathrm{e}^-\) , \(\Delta H = 735 kJ/mol\) 2. \(\mathrm{Mg}^{+}(g) \rightarrow \mathrm{Mg}^{2+}(g) + \mathrm{e}^-\) , \(\Delta H = 1445 kJ/mol\) For \(\mathrm{O}^{2-}\) 3. \(\mathrm{O}(g) + \mathrm{e}^- \rightarrow \mathrm{O}^{-}(g)\) , \(\Delta H = -141 kJ/mol\) 4. \(\mathrm{O}^{-}(g) + \mathrm{e}^- \rightarrow \mathrm{O}^{2-}(g)\) , \(\Delta H = 878 kJ/mol\)
02

Calculate the total energy change to form Mg2+ O2-

Now, calculate the total energy changes required to create the \(\mathrm{Mg}^{2+} \mathrm{O}^{2-}\) ion pair from the gaseous elements: $$\Delta H_{\mathrm{Mg}^{2+} \mathrm{O}^{2-}} = \Delta H_1 + \Delta H_2 + \Delta H_3 + \Delta H_4 = 735 + 1445 - 141 + 878 = 2917 kJ/mol$$
03

Identify the energy changes to form Mg+ and O-

Analyze the energy changes required to create \(\mathrm{Mg}^{+}\) and \(\mathrm{O}^{-}\) ions. For \(\mathrm{Mg}^{+}\) 1. \(\mathrm{Mg}(g) \rightarrow \mathrm{Mg}^{+}(g) + \mathrm{e}^-\) , \(\Delta H = 735 kJ/mol\) For \(\mathrm{O}^{-}\) 3. \(\mathrm{O}(g) + \mathrm{e}^- \rightarrow \mathrm{O}^{-}(g)\) , \(\Delta H = -141 kJ/mol\)
04

Calculate the total energy change to form Mg+ O-

Now, calculate the total energy changes required to create the \(\mathrm{Mg}^{+} \mathrm{O}^{-}\) ion pair from the gaseous elements: $$\Delta H_{\mathrm{Mg}^{+} \mathrm{O}^{-}} = \Delta H_1 + \Delta H_3 = 735 - 141 = 594 kJ/mol$$
05

Compare the energy changes and define stability

Magnesium oxide in the form of \(\mathrm{Mg}^{2+} \mathrm{O}^{2-}\) has a total energy change of \(2917 kJ/mol\), while the formation of \(\mathrm{Mg}^{+} \mathrm{O}^{-}\) has a total energy change of \(594 kJ/mol\). Since both cases involve positive energy changes, neither species is energetically preferred over the constituent atoms. However, as ΔH(Mg2+O2-) > ΔH(Mg+O-), the formation of the latter species requires less energy and is somewhat more energetically favored compared to the former. Keep in mind that these results are based solely on the given energy changes and do not account for any other factors that may influence the overall stability of these species in real systems. In conclusion, although \(\mathrm{Mg}^{2+} \mathrm{O}^{2-}\) is not energetically preferred over the constituent atoms, its formation is more energetically favorable compared to \(\mathrm{Mg}^{+} \mathrm{O}^{-}\). Therefore, magnesium oxide exists as \(\mathrm{Mg}^{2+} \mathrm{O}^{2-}\) rather than \(\mathrm{Mg}^{+} \mathrm{O}^{-}\) based on the given energy changes.

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