Write Lewis structures that obey the octet rule for each of the following molecules and ions. (In each case the first atom listed is the central atom.) a. $\mathrm{POCl}_{3}, \mathrm{SO}_{4}^{2-}, \mathrm{XeO}_{4}, \mathrm{PO}_{4}^{3-}, \mathrm{ClO}_{4}^{-}$ b. $\mathrm{NF}_{3}, \mathrm{SO}_{3}^{2-}, \mathrm{PO}_{3}^{3-}, \mathrm{ClO}_{3}^{-}$ c. \(\mathrm{ClO}_{2}-, \mathrm{SCl}_{2}, \mathrm{PCl}_{2}^{-}\) d. Considering your answers to parts a, b, and c, what conclusions can you draw concerning the structures of species containing the same number of atoms and the same number of valence electrons?

Short Answer

Expert verified
In summary, the Lewis structures of the given molecules and ions obey the octet rule. For species with the same number of atoms and valence electrons, their shapes depend mainly on the arrangement of atoms and electron pairs around the central atom. However, such species might not necessarily have the same shape, as the arrangement of electrons can be influenced by differences in electronegativity and the central atom's ability to expand its valence shell.

Step by step solution

01

a. Lewis structures for \(\mathrm{POCl}_{3}, \mathrm{SO}_{4}^{2-}, \mathrm{XeO}_{4}, \mathrm{PO}_{4}^{3-}, \mathrm{ClO}_{4}^{-}\)

1. First, count the total number of valence electrons for each molecule or ion. 2. Place the least electronegative atom as the central atom. 3. Draw single bonds between the central atom and surrounding atoms. 4. Distribute the remaining electrons to satisfy the octet rule for all atoms. The Lewis structures for each molecule or ion are as follows: \(\mathrm{POCl}_{3}\): \[ \chemfig{P(-[:0]O)(-[:-90]Cl)(-[:90]Cl)(-[:180]Cl)} \] \(\mathrm{SO}_{4}^{2-}\): \[ \chemfig{S(=[:0]O)(=[:90]O)(=[:180]O)(=[:-90]O)}^{-2} \] \(\mathrm{XeO}_{4}\): \[ \chemfig{Xe(=[:0]O)(=[:90]O)(=[:180]O)(=[:-90]O)} \] \(\mathrm{PO}_{4}^{3-}\): \[ \chemfig{P(-[:0]O)(-[:90]O)(-[:180]O)(-[:-90]O)}^{3-} \] \(\mathrm{ClO}_{4}^{-}\): \[ \chemfig{Cl(-[:0]O)(-[:90]O)(-[:180]O)(-[:-90]O)}^{-} \]
02

b. Lewis structures for \(\mathrm{NF}_{3}, \mathrm{SO}_{3}^{2-}, \mathrm{PO}_{3}^{3-}, \mathrm{ClO}_{3}^{-}\)

Follow the same procedure as mentioned earlier for each molecule or ion: \(\mathrm{NF}_{3}\): \[ \chemfig{N(-[1]F)(-[3]F)(-[5]F)} \] \(\mathrm{SO}_{3}^{2-}\): \[ \chemfig{S(-[:0]O)(-[:120]O)(-[:-120]O)}^{2-} \] \(\mathrm{PO}_{3}^{3-}\): \[ \chemfig{P(-[:0]O)(-[:90]O)(-[:-90]O)}^{3-} \] \(\mathrm{ClO}_{3}^{-}\): \[ \chemfig{Cl(-[:0]O)(-[:90]O)(-[:-90]O)}^{-} \]
03

c. Lewis structures for \(\mathrm{ClO}_{2}-, \mathrm{SCl}_{2}, \mathrm{PCl}_{2}^{-}\)

Follow the same procedure as mentioned earlier for each molecule or ion: \(\mathrm{ClO}_{2}^{-}\): \[ \chemfig{Cl(=[:0]O)(-[:-90]O)}^{-} \] \(\mathrm{SCl}_{2}\): \[ \chemfig{S(-[:0]Cl)(-[:-90]Cl)} \] \(\mathrm{PCl}_{2}^{-}\): \[ \chemfig{P(-[:0]Cl)(-[:-90]Cl)}^{-} \]
04

d. Conclusions

From the Lewis structures of species containing the same number of atoms and valence electrons, we can draw the following conclusions: 1. The shape of the molecules or ions depends on the arrangement of atoms and electron pairs around the central atom. 2. Species with the same number of atoms and valence electrons might not necessarily have the same shape. 3. Species with different central atoms, even though they might have the same number of atoms and valence electrons, will have different arrangements of electrons due to differences in electronegativity and the central atom's ability to expand its valence shell.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write electron configurations for a. the cations \(\mathrm{Sr}^{2+}, \mathrm{Cs}^{+}, \mathrm{In}^{+},\) and \(\mathrm{Pb}^{2+} .\) b. the anions \(\mathrm{P}^{3-}, \mathrm{S}^{2-},\) and \(\mathrm{Br}^{-}\)

List all the possible bonds that can occur between the elements P, Cs, O, and H. Predict the type of bond (ionic, covalent, or polar covalent) one would expect to form for each bond.

A toxic cloud covered Bhopal, India, in December 1984 when water leaked into a tank of methyl isocyanate, and the product escaped into the atmosphere. Methyl isocyanate is used in the production of many pesticides. Draw the Lewis structure for methyl isocyanate, \(\mathrm{CH}_{3} \mathrm{NCO}\), including resonance forms. The skeletal structure is

Use the following data to estimate \(\Delta H_{f}^{\circ}\) for potassium chloride. $$\mathrm{K}(s)+\frac{1}{2} \mathrm{Cl}_{2}(g) \longrightarrow \mathrm{KCl}(s)$$ $\begin{array}{l}{\text { Lattice energy }} & {-690 . \mathrm{kJ} / \mathrm{mol}} \\ {\text { Ionization energy for } \mathrm{K}} & \quad{419 \mathrm{kJ} / \mathrm{mol}} \\ {\text { Electron affinity of } \mathrm{Cl}} & {-349 \mathrm{kJ} / \mathrm{mol}}\\\\{\text { Bond energy of } \mathrm{Cl}_{2}} & \quad {239 \mathrm{kJ} / \mathrm{mol}} \\ {\text { Enthalpy of sublimation for } \mathrm{K}} & \quad {90 . \mathrm{kJ} / \mathrm{mol}}\end{array}$

Consider the following bond lengths: $$\mathrm{C}-\mathrm{O} \quad 143 \mathrm{pm} \quad \mathrm{C}=\mathrm{O} \quad 123 \mathrm{pm} \quad \mathrm{C} \equiv \mathrm{O} \quad 109 \mathrm{pm}$$ In the \(\mathrm{CO}_{3}^{2-}\) ion, all three \(\mathrm{C}-\mathrm{O}\) bonds have identical bond lengths of 136 \(\mathrm{pm} .\) Why?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free