Chapter 8: Problem 96

Borazine \(\left(\mathrm{B}_{3} \mathrm{N}_{3} \mathrm{H}_{6}\right)\) has often been called "inorganic" benzene. Write Lewis structures for borazine. Borazine contains a six-membered ring of alternating boron and nitrogen atoms with one hydrogen bonded to each boron and nitrogen.

Short Answer

Expert verified

The Lewis structure for borazine \(\mathrm{(B}_{3} \mathrm{N}_{3} \mathrm{H}_{6})\) can be drawn as follows: ``` H | N = B - N | | B - N = B | H ``` The structure consists of a six-membered ring with alternating boron and nitrogen atoms, with each atom bonded to a hydrogen. The octet rule is satisfied for all atoms.

Step by step solution

Calculate Valence Electrons

First, let's find the total number of valence electrons in borazine. In order to do so, we need to know the number of valence electrons for each element. Boron (B) has 3 valence electrons, Nitrogen (N) has 5 valence electrons, and Hydrogen (H) has 1 valence electron. Since there are 3 Boron, 3 Nitrogen, and 6 Hydrogen atoms in Borazine: Total valence electrons = (3 x 3) + (3 x 5) + (6 x 1) = 9 + 15 + 6 = 30.

Draw the Skeleton Structure

As mentioned, borazine contains a six-membered ring of alternating boron and nitrogen atoms, with hydrogen atoms bonded to boron and nitrogen. Start by drawing the ring of alternating B and N atoms, and then add the hydrogen atoms bonded to each B and N atom: ``` H | N---B---N | | B---N---B | H ```

Add the Electrons

Place the electrons around each atom, starting with the bonds between the atoms. Each bond in the molecule represents 2 shared electrons, so we've used 12 electrons for these 6 bonds. Now we need to add the 18 remaining electrons (30 total valence electrons - 12 used for bonds). Nitrogen atom requires 3 more electrons and hydrogen atom requires 1 more electron to fulfill the octet rule (2 electrons for hydrogen). We can add the remaining electrons to satisfy the octet rule for nitrogen atoms: ``` H | N = B - N | | B - N = B | H ```

Check the Octet Rule

Now that we have placed all the electrons in the structure, let's check if each atom follows the octet rule (2 electrons for hydrogen). Each nitrogen atom has 8 electrons around it, each boron atom has 6 electrons, and hydrogen atoms have 2 electrons. Since all atoms follow the octet rule, our Lewis structure is complete: ``` H | N = B - N | | B - N = B | H ``` This is the Lewis structure for borazine (B3N3H6).

Unlock Step-by-Step Solutions & Ace Your Exams!

Full Textbook Solutions
Get detailed explanations and key concepts
Unlimited Al creation
Al flashcards, explanations, exams and more...
Ads-free access
To over 500 millions flashcards
Money-back guarantee
We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Borazine \(\left(\mathrm{B}_{3} \mathrm{N}_{3} \mathrm{H}_{6}\right)\) has often been called "inorganic" benzene. Write Lewis structures for borazine. Borazine contains a six-membered ring of alternating boron and nitrogen atoms with one hydrogen bonded to each boron and nitrogen.

Short Answer

Step by step solution

Calculate Valence Electrons

Draw the Skeleton Structure

Add the Electrons

Check the Octet Rule

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Physical Chemistry

Chemical Analysis

Nuclear Chemistry

The Earths Atmosphere

Kinetics

Chemistry Branches

Study anywhere. Anytime. Across all devices.