Do the following statements describe chemical or physical properties? (a) Oxygen gas supports combustion. (b) Fertilizers help to increase agricultural production. (c) Water boils below \(100^{\circ} \mathrm{C}\) on top of \(\mathrm{a}\) mountain. (d) Lead is more dense than aluminum. (e) Uranium is a radioactive element.

Short Answer

Expert verified
(a) Chemical (b) Chemical (c) Physical (d) Physical (e) Chemical

Step by step solution

01

Analyzing Statement (a)

Oxygen gas supports combustion. Combustion is a chemical reaction that usually happens with oxygen and results in the release of heat and light. Thus, this statement describes a chemical property.
02

Analyzing Statement (b)

Fertilizers help to increase agricultural production. Fertilizers provide essential plant nutrients thereby improving productivity which is actually a use, not a physical or chemical property. However, on a deeper note, they bring about this change by modifying the chemical property of the soil. Thus, the action of fertilizers could be seen as a chemical property.
03

Analyzing Statement (c)

Water boils below \(100^{\circ} \mathrm{C}\) on top of a mountain. Boiling point is a physical property, not a chemical one, as the water does not go through a chemical change when it boils (it remains water before and after the boiling process). Thus, this statement describes a physical property.
04

Analyzing Statement (d)

Lead is more dense than aluminum. Density is a physical property as it defines the amount of mass per unit volume of the substance without a change in the chemical composition. Thus, this statement describes a physical property.
05

Analyzing Statement (e)

Uranium is a radioactive element. Radioactivity refers to the spontaneous emission of radiation by an unstable atomic nucleus, a process that involves a change in the composition of the nucleus and is thus a chemical property. Thus, this statement describes a chemical property.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Carry out the following conversions: (a) \(70 \mathrm{~kg}\), the average weight of a male adult, to pounds. (b) 14 billion years (roughly the age of the universe) to seconds. (Assume there are 365 days in a year.) (c) \(7 \mathrm{ft} 6 \mathrm{in},\) the height of the basketball player \(\mathrm{Yao}\) Ming, to meters. (d) \(88.6 \mathrm{~m}^{3}\) to liters.

Give an example of a homogeneous mixture and an example of a heterogeneous mixture.

How does an intensive property differ from an extensive property? Which of the following properties are intensive and which are extensive? (a) length, (b) volume, (c) temperature, (d) mass.

A chemist mixes two liquids \(A\) and \(B\) to form a homogeneous mixture. The densities of the liquids are \(2.0514 \mathrm{~g} / \mathrm{mL}\) for \(\mathrm{A}\) and \(2.6678 \mathrm{~g} / \mathrm{mL}\) for \(\mathrm{B}\). When she drops a small object into the mixture, she finds that the object becomes suspended in the liquid; that is, it neither sinks nor floats. If the mixture is made of 41.37 percent \(A\) and 58.63 percent \(B\) by volume, what is the density of the metal? Can this procedure be used in general to determine the densities of solids? What assumptions must be made in applying this method?

A cylindrical glass bottle \(21.5 \mathrm{~cm}\) in length is tilled with cooking oil of density \(0.953 \mathrm{~g} / \mathrm{mL}\). If the mass of the oil needed to fill the bottle is \(1360 \mathrm{~g}\), calculate the inner diameter of the bottle.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free