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Chapter 1: Problem 32

Express the wing numbers as decimals: (a) \(1.52 \times 10^{-2},\) (b) \(7.78 \times 10^{-8}\)

Short Answer

Expert verified
The decimal equivalents are (a) \(0.0152\) and (b) \(0.0000000778\).

Step by step solution

01

Convert \(1.52 \times 10^{-2}\) to decimal

Start by understanding what \(-2\) power of \(10\) means in this context. It means divide \(1.52\) by \(100\) or move the decimal point two places to the left. That gives us \(0.0152\).
02

Convert \(7.78 \times 10^{-8}\) to decimal

A similar approach is used for the second part. The \(-8\) exponent of \(10\) means divide \(7.78\) by \(100000000\) or move the decimal point eight places to the left, resulting in \(0.0000000778\).

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Most popular questions from this chapter

The radius of a copper (Cu) atom is roughly \(1.3 \times\) \(10^{-10} \mathrm{~m} .\) How many times can you divide evenly a piece of \(10-\mathrm{cm}\) copper wire until it is reduced to two separate copper atoms? (Assume there are appropriate tools for this procedure and that copper atoms are lined up in a straight line, in contact with each other. Round off your answer to an integer.)

Carry out the following conversions: (a) \(70 \mathrm{~kg}\), the average weight of a male adult, to pounds. (b) 14 billion years (roughly the age of the universe) to seconds. (Assume there are 365 days in a year.) (c) \(7 \mathrm{ft} 6 \mathrm{in},\) the height of the basketball player \(\mathrm{Yao}\) Ming, to meters. (d) \(88.6 \mathrm{~m}^{3}\) to liters.

The following procedure was used to determine the volume of a flask. The flask was weighed dry and then filled with water. If the masses of the empty flask and filled flask were \(56.12 \mathrm{~g}\) and \(87.39 \mathrm{~g},\) respectively, and the density of water is \(0.9976 \mathrm{~g} / \mathrm{cm}^{3}\), calculate the volume of the flask in \(\mathrm{cm}^{3}\).

You are given a liquid. Briefly describe steps you would take to show whether it is a pure substance or a homogeneous mixture.

In water conservation, chemists spread a thin film of a certain inert material over the surface of water to cut down on the rate of evaporation of water in reservoirs. This technique was pioneered by Benjamin Franklin three centuries ago. Franklin found that \(0.10 \mathrm{~mL}\) of oil could spread over the surface of water about \(40 \mathrm{~m}^{2}\) in area. Assuming that the oil forms a monolayer, that is, a layer that is only one molecule thick, estimate the length of each oil molecule in nanometers. $\left(1 \mathrm{nm}=1 \times 10^{-9} \mathrm{~m} .\right).
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