Express the answers to the following calculations in scientific notation: (a) \(145.75+\left(2.3 \times 10^{-1}\right)\) (b) \(79,500 \div\left(2.5 \times 10^{2}\right)\) (c) \(\left(7.0 \times 10^{-3}\right)-\left(8.0 \times 10^{-4}\right)\) (d) \(\left(1.0 \times 10^{4}\right) \times\left(9.9 \times 10^{6}\right)\)

Short Answer

Expert verified
(a) \(1.4805 \times 10^{2}\), (b) \(3.18 \times 10^{2}\), (c) \(6.2 \times 10^{-3}\), (d) \(9.9 \times 10^{10}\)

Step by step solution

01

Addition

(a) To perform the operation \(145.75+(2.3 \times 10^{-1})\), first convert \(145.75\) into scientific notation, obtaining \(1.4575 \times 10^{2}\). Then, add \(1.4575 \times 10^{2}\) to \(2.3 \times 10^{-1}\) by bringing them to the common exponent, here \(10^{2}\). We get \(1.4575 \times 10^{2} + 0.023 \times 10^{2} = 1.4805 \times 10^{2}\).
02

Division

(b) In the equation \(79500 \div(2.5 \times 10^{2})\), first, express \(79500\) in scientific notation as \(7.95 \times 10^{4}\). Then, divide \(7.95 \times 10^{4}\) by \(2.5 \times 10^{2}\). This yields \(7.95 \times 10^{4-2} \div 2.5 = 3.18 \times 10^{2}\).
03

Subtraction

(c) In order to subtract \((7.0 \times 10^{-3})-(8.0 \times 10^{-4})\), bring them to a common exponent, here \(10^{-3}\). We get \(7.0 \times 10^{-3} - 0.8 \times 10^{-3} = 6.2 \times 10^{-3}\).
04

Multiplication

(d) The multiplication operation \((1.0 \times 10^{4}) \times (9.9 \times 10^{6})\) simplifies by multiplying the numbers and adding the exponents to get \(1.0 \times 9.9 \times 10^{4+6} = 9.9 \times 10^{10}\).

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Most popular questions from this chapter

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