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Chapter 1: Problem 61

The following procedure was used to determine the volume of a flask. The flask was weighed dry and then filled with water. If the masses of the empty flask and filled flask were \(56.12 \mathrm{~g}\) and \(87.39 \mathrm{~g},\) respectively, and the density of water is \(0.9976 \mathrm{~g} / \mathrm{cm}^{3}\), calculate the volume of the flask in \(\mathrm{cm}^{3}\).

Short Answer

Expert verified
The volume of the flask is 31.34 cm³.

Step by step solution

01

Calculate the mass of the water

Subtract the mass of the empty flask from the mass of the filled flask. This gives the mass of the water. \(Mass_{water} = Mass_{filled flask} - Mass_{empty flask} = 87.39g - 56.12g = 31.27g\).
02

Use the density formula to calculate the volume

The density formula is \(density = mass / volume\). This can be rearranged to find the volume: \(volume = mass / density\). The mass is 31.27g and the density of water is 0.9976g/cm³. Substituting these values in gives: \(volume = 31.27g / 0.9976g/cm³ = 31.34 cm³\)

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Most popular questions from this chapter

Give the names of the elements represented by the chemical symbols \(\mathrm{Li}, \mathrm{F}, \mathrm{P}, \mathrm{Cu}, \mathrm{As}, \mathrm{Zn}, \mathrm{Cl}, \mathrm{Pt}, \mathrm{Mg},\) \(\mathrm{U}, \mathrm{Al}, \mathrm{Si},\) Ne. (See Table 1.1 and the list of The Elements with Their Symbols and Atomic Masses.)

Measurements show that \(1.0 \mathrm{~g}\) of iron (Fe) contains \(1.1 \times 10^{22}\) Fe atoms. How many Fe atoms are in \(4.9 \mathrm{~g}\) of Fe, which is the total amount of iron in the body of an average adult?

A human brain weighs about \(1 \mathrm{~kg}\) and contains about \(10^{11}\) cells. Assuming that each cell is com pletely filled with water (density \(=1 \mathrm{~g} / \mathrm{mL}\) ), calculate the length of one side of such a cell if it were a cube. If the cells are spread out in a thin layer that is a single cell thick, what is the surface area in square meters?

Carry out the following operations as if they were calculations of experimental results, and express each answer in the correct units with the correct number of significant figures: (a) \(5.6792 \mathrm{~m}+0.6 \mathrm{~m}+4.33 \mathrm{~m}\) (b) \(3.70 \mathrm{~g}-2.9133 \mathrm{~g}\) (c) \(4.51 \mathrm{~cm} \times 3.6666 \mathrm{~cm}\) (d) \(\left(3 \times 10^{4} \mathrm{~g}+6.827 \mathrm{~g}\right) /\left(0.043 \mathrm{~cm}^{3}-0.021 \mathrm{~cm}^{3}\right)\)

Suppose that a new temperature scale has been devised on which the melting point of ethanol \(\left(-117.3^{\circ} \mathrm{C}\right)\) and the boiling point of ethanol \(\left(78.3^{\circ} \mathrm{C}\right)\) are taken as \(0^{\circ} \mathrm{S}\) and \(100^{\circ} \mathrm{S},\) respectively where \(S\) is the symbol for the new temperature scale. Derive an equation relating a reading on this scale to a reading on the Celsius scale. What would this thermometer read at \(25^{\circ} \mathrm{C}\) ?
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