Chapter 1: Problem 81
The men's world record for running a mile outdoors (as of 1999 ) is 3 min 43.13 s. At this rate, how long would it take to run a \(1500-\mathrm{m}\) race? \((1 \mathrm{mi}\) \(=1609 \mathrm{~m} .)\)
Short Answer
Expert verified
It would take approximately 3 minutes and 28 seconds to run a 1500 m race at the same speed as the world record speed for running a mile outdoors.
Step by step solution
01
Convert speed into meters per second
First, it is necessary to convert the speed of running a mile into meters per second. To do that, convert the reported world record time into seconds: \(3 \text{ min}\) is \(3 \times 60 = 180 \) seconds, so the total time is \(180.13 \) seconds. Since 1 mile equals 1609 meters, the speed is calculates as follows: \(\frac{1609}{180.13}\) m/s
02
Calculate time needed to run 1500m
Next, calculate the time it would take to run a 1500m race. This is done by dividing the race distance by the calculated speed: \( \frac{1500}{\frac{1609}{180.13}}\).
03
Convert the time back into minutes and seconds
Finally, convert the calculated time in seconds back into minutes and seconds. This is done by dividing the number of seconds by 60 to get the minutes and taking the remainder as the number of seconds.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Unit Conversion
Understanding unit conversion is essential in various scientific calculations, including physics and chemistry. Converting units helps us compare, communicate, and solve problems that involve different measurement systems. A common example is the conversion between miles and meters or seconds to minutes. In the context of running speed, especially relevant in exercises involving athletes' records, one must be adept at converting time units and distance units to determine performance across standard distances.
For instance, when a world record is given in minutes and seconds for a mile run, and we want to know how this translates to a different race length in meters, we firstly convert the entire time into the smallest unit, usually seconds. Similarly, the mileage is converted to meters, using the conversion factor that 1 mile equals 1609 meters. These conversions are essential to harmonize the units, enabling us to perform accurate and meaningful calculations.
For instance, when a world record is given in minutes and seconds for a mile run, and we want to know how this translates to a different race length in meters, we firstly convert the entire time into the smallest unit, usually seconds. Similarly, the mileage is converted to meters, using the conversion factor that 1 mile equals 1609 meters. These conversions are essential to harmonize the units, enabling us to perform accurate and meaningful calculations.
Time-Distance Calculations
Time-distance calculations are fundamental in kinematics, a branch of mechanics in physics. This area deals with the motion of objects without considering the forces that cause this motion. To calculate the time it will take to cover a certain distance at a constant speed, you use the basic formula: time (t) = distance (d) / speed (s).
Applying this formula to real-world problems, such as predicting the time it would take for an athlete to run a specific distance given their recorded speed, requires careful attention to unit consistency. After we have converted all of our units appropriately, as described in the unit conversion section, we can seamlessly insert the known values into this formula to find the unknown time or distance, as long as we ensure that the speed unit matches the distance and time units involved in the calculation.
Applying this formula to real-world problems, such as predicting the time it would take for an athlete to run a specific distance given their recorded speed, requires careful attention to unit consistency. After we have converted all of our units appropriately, as described in the unit conversion section, we can seamlessly insert the known values into this formula to find the unknown time or distance, as long as we ensure that the speed unit matches the distance and time units involved in the calculation.
Speed Calculations in Physics
Speed calculations are a core part of solving physics problems, particularly when analyzing motion. Speed is defined as the distance traveled per unit of time and is typically expressed as meters per second (m/s) in the SI unit system. To find speed, the formula used is speed (s) = distance (d) / time (t).
In problems that involve converting an athlete's speed from a mile race to a 1500-meter race, one calculates the speed by taking the total distance of the mile in meters and dividing it by the time it took to run that distance in seconds. With this speed, we can then find out how long it would take to run any other distance, by rearranging the same speed formula to find the variable of interest, in this case, time. Knowing how to manipulate this formula is crucial in physics to address a variety of problems, from simple athletics races to complex movements in planetary orbits.
In problems that involve converting an athlete's speed from a mile race to a 1500-meter race, one calculates the speed by taking the total distance of the mile in meters and dividing it by the time it took to run that distance in seconds. With this speed, we can then find out how long it would take to run any other distance, by rearranging the same speed formula to find the variable of interest, in this case, time. Knowing how to manipulate this formula is crucial in physics to address a variety of problems, from simple athletics races to complex movements in planetary orbits.
Mathematical Problem-Solving in Chemistry
Mathematical problem-solving is not limited to physics; it is also a staple in chemistry. While it might seem that chemistry is solely about reactions and elements, much of the discipline relies on quantitative calculations. This includes determining concentration, calculating reaction yields, and predicting reaction rates. What ties this to our running example is the disciplined approach to problem-solving.
One begins with understanding the problem, identifying known and unknown variables, and then selecting and applying the correct formula. Unit conversions are often necessary in chemistry, just as with speed and time calculations, such as converting between moles and grams or liters and milliliters. Additionally, stoichiometry, which deals with the quantitative relationships of the substances as they participate in chemical reactions, often requires methodical step-by-step approaches similar to those used in determining running speeds and times.
One begins with understanding the problem, identifying known and unknown variables, and then selecting and applying the correct formula. Unit conversions are often necessary in chemistry, just as with speed and time calculations, such as converting between moles and grams or liters and milliliters. Additionally, stoichiometry, which deals with the quantitative relationships of the substances as they participate in chemical reactions, often requires methodical step-by-step approaches similar to those used in determining running speeds and times.