Which of the following ions possess a dipole moment: (a) \(\mathrm{ClF}_{2}^{+},\) (b) \(\mathrm{ClF}_{2}^{-},\) (c) \(\mathrm{IF}_{4}^{+},\) (d) \(\mathrm{IF}_{4}^{-} ?\)

Short Answer

Expert verified
Among the give ions, only \(\mathrm{ClF}_{2}^{+}\), and \(\mathrm{ClF}_{2}^{-}\) possess a dipole moment, while \(\mathrm{IF}_{4}^{+}\), and \(\mathrm{IF}_{4}^{-}\) do not.

Step by step solution

01

Analyzing the geometry of \(\mathrm{ClF}_{2}^{+}\)

This ion has a bent shaped molecular geometry, like that of water. Because the two Fluorine atoms and the non-bonding pair of electron are not distributed symmetrically around the Chlorine atom, the molecule is polarized and thus has a dipole moment.
02

Analyzing the geometry of \(\mathrm{ClF}_{2}^{-}\)

This ion too has a bent shaped geometry. But due to the extra negative charge, it has one more non-bonding pair of electrons. But like \(\mathrm{ClF}_{2}^{+}\), the Fluorine atoms and the non-bonding pairs of electrons are not distributed symmetrically around the Chlorine atom, creating a dipole moment.
03

Analyzing the geometry of \(\mathrm{IF}_{4}^{+}\)

The electron configuration of Iodine in its ground state allows this ion to form a square planar geometry. In this configuration, the charge distribution is symmetric, cancelling the dipole moments, hence \(\mathrm{IF}_{4}^{+}\) has no dipole moment.
04

Analyzing the geometry of \(\mathrm{IF}_{4}^{-}\)

Like \(\mathrm{IF}_{4}^{+}\), \(\mathrm{IF}_{4}^{-}\) also forms a square planar geometry with symmetric charge distribution, cancelling the dipole moments. Thus, it does not possess a dipole moment.

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