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Chapter 10: Problem 44

How many pi bonds and sigma bonds are there in the tetracyanoethylene molecule?

Short Answer

Expert verified
In the tetracyanoethylene molecule, there are a total of 7 sigma bonds and 5 pi bonds.

Step by step solution

01

Drawing the Lewis Structure

The first step is to draw the Lewis Structure of the molecule. The formula for tetracyanoethylene is C6N4. Ethanediyl group (ethene) is situated in the middle, between two cyanide groups. After drawing the structure, you should have a molecule with a carbon double bond (ethene) in the center, and each of these carbons are singly bonded to a carbon that precedes nitrogen with a triple bond.
02

Identifying the Sigma Bonds

Sigma bonds are single covalent bonds. In the drawn structure, there are 7 sigma bonds in total. There are three in the ethene portion of the molecule (one C=C and two C-C bonds), and two each in both cyanide portions of the molecule (C-N and C-C for each side).
03

Identifying the Pi Bonds

Pi bonds are part of double or triple covalent bonds (one part of the bond is sigma, the remaining are pi). In the drawn structure, there are 5 pi bonds in total. There is one in the ethene portion (double bond has one sigma and one pi bond, so the pi bond is 1 here), and two each in both cyanide portions - each having one triple bond (one sigma and two pi).

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