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Chapter 10: Problem 84

Which of the following molecules and ions are linear? \(\mathrm{ICl}_{2}^{-}, \mathrm{IF}_{2}^{+}, \mathrm{OF}_{2}, \mathrm{SnI}_{2}, \mathrm{CdBr}_{2}\)

Short Answer

Expert verified
\(\mathrm{SnI}_{2}\) and \(\mathrm{CdBr}_{2}\) are linear.

Step by step solution

01

Determine central atom

Identify the central atom for each molecule. Typically, the atom with the lowest electronegativity is the central atom. In \(\mathrm{ICl}_{2}^{-}\), \(\mathrm{IF}_{2}^{+}\), \(\mathrm{OF}_{2}\), the central atom is I, F, and O respectively. For \(\mathrm{SnI}_{2}\) and \(\mathrm{CdBr}_{2}\), the central atoms are Sn and Cd, respectively.
02

Determine electron domain

Determine the electron domains around these atoms. Electron domains are regions around the central atom where electrons are likely to be found. They include bonding pairs and non-bonding pairs. \(\mathrm{ICl}_{2}^{-}\) and \(\mathrm{IF}_{2}^{+}\) each have 3 electron domains, \(\mathrm{OF}_{2}\) has 4 electron domains, and \(\mathrm{SnI}_{2}\), \(\mathrm{CdBr}_{2}\) have only 2 electron domains each.
03

Determine molecular shape

Following the VSEPR theory, the shape of a molecule depends on the number of electron domains around the central atom. While 2 domains result in a linear shape, 3 or 4 domains result in a bent or trigonal planar, and tetrahedral shapes, respectively. Therefore, only \(\mathrm{SnI}_{2}\) and \(\mathrm{CdBr}_{2}\) are linear.

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Most popular questions from this chapter

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