Arrange the following compounds in order of increasing solubility in water: \(\mathrm{O}_{2}, \mathrm{LiCl}, \mathrm{Br}_{2},\) methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\)

Short Answer

Expert verified
The order of increasing solubility in water of the compounds is: \(O_2 < Br_2 < CH_{3}OH < LiCl\)

Step by step solution

01

Identify the polarity or ionic nature of each compound

Water, \(H_2O\), is a polar solvent. Identify the solubility of each compound based on whether it is ionic, polar or nonpolar. \(O_2\) and \(Br_2\) are nonpolar; \(LiCl\) is ionic; and \(CH_{3}OH\) is polar.
02

Order compounds based on 'like dissolves like'

Nonpolar compounds are least soluble in water, therefore \(O_2\) and \(Br_2\) are first in the order. Among them, since oxygen is a smaller molecule compared to bromine, it can have less effective nonpolar interactions and thus is slightly more soluble than bromine. So, arrange \(O_2\) before \(Br_2\). Polar methanol is highly soluble as it can interact with water through hydrogen bonding. So it comes next.
03

Place ionic compound in the order

Ionic compounds are most soluble in water. According to solubility rules, all chloride salts except those of silver, mercury, and lead are soluble, so \(LiCl\) comes last as the most soluble.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polarity of Compounds
Understanding the polarity of compounds is essential when studying solubility. A molecule is polar if it has a separation of charge, meaning one part of the molecule has a slight positive charge and another part has a slight negative charge. This usually happens due to differences in electronegativity between the atoms that are bonded together. For instance, water is a polar molecule because oxygen is more electronegative than hydrogen, creating a dipole moment.

Now, why does polarity affect solubility? In a mixture, polar molecules will preferentially interact with other polar substances, including solvents like water. This is because they can form favorable electrostatic interactions, which help them dissolve. Nonpolar molecules like \(O_2\) and \(Br_2\), on the other hand, do not have this kind of charge separation and tend to aggregate together, limiting their solubility in a polar solvent such as water.
Like Dissolves Like Principle
The 'like dissolves like' principle is a simple rule that helps predict solubility behavior: polar solvents tend to dissolve polar or ionic substances, and nonpolar solvents tend to dissolve nonpolar substances. This principle stems from the fact that similar types of intermolecular forces exist between molecules of the solvent and the solute. In our example, methanol \(CH_3OH\) is polar and therefore dissolves readily in water, also polar, due to favorable intermolecular interactions.

The principle explains why nonpolar gases like \(O_2\) and \(Br_2\) have low solubility in water. Without significant intermolecular forces to break up the lattice of the solid or interactions in the gas, these substances do not integrate well with the structure of water.
Ionic and Molecular Compounds
The distinction between ionic and molecular compounds is also crucial when it comes to solubility in water. Ionic compounds, like \(LiCl\), consist of positively and negatively charged ions held together by strong electrostatic forces in a crystal lattice. When introduced to water, the polar water molecules surround and stabilize the ions, breaking apart the lattice and leading to high solubility.

Molecular compounds can be polar, like methanol, or nonpolar, like \(O_2\) and \(Br_2\). Polar molecular compounds tend to be more soluble in water than nonpolar ones because they can form favorable intermolecular interactions with water. Methanol, which can form hydrogen bonds with water, provides a good example of a soluble polar molecule.
Hydrogen Bonding
Hydrogen bonding plays a pivotal role in the solubility of compounds in water. It's a special type of dipole-dipole attraction that occurs between a hydrogen atom bonded to a highly electronegative atom (usually nitrogen, oxygen, or fluorine) and another electronegative atom with a lone pair of electrons. Methanol has a hydroxyl (-OH) group that can engage in hydrogen bonding with water molecules, significantly increasing its solubility.

In addition, the ability of a substance to form hydrogen bonds with water increases the dissolution process. This explains why methanol, capable of acting both as a hydrogen bond donor (owing to its hydrogen) and acceptor (owing to its oxygen), is highly soluble in water, whereas nonpolar substances, which cannot form hydrogen bonds, exhibit much less solubility in water.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Both \(\mathrm{NaCl}\) and \(\mathrm{CaCl}_{2}\) are used to melt ice on roads and sidewalks in winter. What advantages do these substances have over sucrose or urea in lowering the freezing point of water?

The solubility of \(\mathrm{N}_{2}\) in blood at \(37^{\circ} \mathrm{C}\) and at a partial pressure of \(0.80 \mathrm{~atm}\) is \(5.6 \times 10^{-4} \mathrm{~mol} / \mathrm{L} .\) A deep-sea diver breathes compressed air with the partial pressure of \(\mathrm{N}_{2}\) equal to 4.0 atm. Assume that the total volume of blood in the body is \(5.0 \mathrm{~L}\). Calculate the amount of \(\mathrm{N}_{2}\) gas released (in liters at \(37^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\) ) when the diver returns to the surface of the water, where the partial pressure of \(\mathrm{N}_{2}\) is \(0.80 \mathrm{~atm}\)

What is the osmotic pressure (in atm) of a \(1.36 M\) aqueous solution of urea \(\left[\left(\mathrm{NH}_{2}\right)_{2} \mathrm{CO}\right]\) at \(22.0^{\circ} \mathrm{C} ?\)

The vapor pressures of ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) and 1 -propanol \(\left(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{OH}\right)\) at \(35^{\circ} \mathrm{C}\) are \(100 \mathrm{mmHg}\) and \(37.6 \mathrm{mmHg},\) respectively. Assume ideal behavior and calculate the partial pressures of ethanol and 1-propanol at \(35^{\circ} \mathrm{C}\) over a solution of ethanol in 1-propanol, in which the mole fraction of ethanol is \(0.300 .\)

Here is an after-dinner trick. With guests still sitting at the table, the host provided each of them with a glass of water containing an ice cube floating on top and a piece of string about \(2-3\) in. in length. He then asked them to find a way to lift the ice cube without touching it by hand or using any other objects such as a spoon or fork. Explain how this task can be accomplished. (Hint: The table had not been cleared so the salt and pepper shakers were still there.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free