How do the solubilities of most ionic compounds in water change with temperature? With pressure?

Short Answer

Expert verified
The solubilities of most ionic compounds in water increase with temperature and are largely unaffected by pressure changes. However, for gases dissolved in liquids, increased pressure results in increased solubility in accordance with Henry's Law.

Step by step solution

01

Solubility and Temperature

First, consider how temperature affects the solubility of ionic compounds in water. For most ionic compounds, solubility usually increases with increasing temperature. This happens because the process of dissolving an ionic compound in water is usually endothermic. When an ionic compound dissolves, its ions separate and spread out in the water, absorbing heat energy from the surroundings. As the temperature rises, more energy becomes available to overcome the forces holding the ions together, and more of the compound can dissolve.
02

Solubility and Pressure

When considering pressure, it does not affect the solubility of solid or liquid solutes in a significant way. This is because solids and liquids are essentially incompressible – their volume does not change with pressure. However, for gases dissolved in liquids, increased pressure leads to increased solubility. This relationship is described by Henry's Law which only applies to gases.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Effect of Temperature on Solubility
Temperature plays a crucial role in determining the solubility of ionic compounds in water. In essence, as the temperature rises, the solubility of many ionic compounds increases. This is due to the kinetic energy of the molecules: warmer temperatures mean molecules are moving more energetically, thus more capable of breaking apart the ionic lattice of a compound and integrating the ions into the solution.

For students visualizing this process, imagine a crowd of people (the water molecules) energetically welcoming new friends (the ions) into a dance floor—that's the dissolving process at higher temperatures! With greater energy (heat), there's a tendency for more robust interactions and a higher number of these 'friendships' to form, resulting in increased solubility. It's an accessible way to remember how heat affects the solvation process.
Endothermic Dissolution
Endothermic dissolution refers to the process where absorbing heat is necessary for a solute to dissolve in a solvent. For ionic compounds, the separation of ions from their solid structure requires energy because this breakup involves overcoming strong ionic bonds. It's akin to needing energy to pull apart magnets that are stuck together.

In the case of endothermic dissolution, you can think of the dissolved ionic compound as your body feeling chilly and needing warmth (heat from the surrounding water) to 'get comfortable' (dissolve). This warmth helps the compound 'relax' into its ionic components, thus increasing solubility. Remember, if the dissolution process seems to 'prefer' a warm environment, it's likely endothermic!
Effect of Pressure on Solubility
Pressure's effect on solubility is a bit discriminate—it's not a one-size-fits-all kind of influence. For solids and liquids, squeezing them doesn't really make them want to dissolve more or less; their solubility isn't significantly affected by pressure since their volumes are quite resistant to change. It's like pressing on a packed suitcase; no matter how much you push, you can't fit more clothes in.

However, for gases, the story unfolds differently. Imagine a balloon under pressure—it gets denser. Similarly, when you pressurize a gas, its molecules are 'squeezed' closer together and more of them can be 'stuffed' into the liquid. It's a principle often used by scuba divers who need oxygen to dissolve in their blood under high-pressure underwater conditions.
Henry's Law
Henry's Law gives us a scientific view of how gases behave with regard to solubility and pressure. It states that at a constant temperature, the amount of gas that dissolves in a liquid is directly proportional to the pressure of that gas above the liquid. So, for gas solubility, the higher the pressure, the more gas will dissolve, assuming the temperature is kept steady.

Visualize a soda bottle—before opening, the gas above the liquid is pressurized, keeping more carbon dioxide dissolved. When you open the bottle, pressure drops and the gas escapes with a fizz. That's Henry's Law in your daily life! This law is vital for understanding how gases will behave under different pressure conditions and is essential for industries involving carbonated beverages, deep-sea diving equipment, and even in medical treatments where gas solubility in blood is a concern.

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Most popular questions from this chapter

The solubility of \(\mathrm{N}_{2}\) in blood at \(37^{\circ} \mathrm{C}\) and at a partial pressure of \(0.80 \mathrm{~atm}\) is \(5.6 \times 10^{-4} \mathrm{~mol} / \mathrm{L} .\) A deep-sea diver breathes compressed air with the partial pressure of \(\mathrm{N}_{2}\) equal to 4.0 atm. Assume that the total volume of blood in the body is \(5.0 \mathrm{~L}\). Calculate the amount of \(\mathrm{N}_{2}\) gas released (in liters at \(37^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\) ) when the diver returns to the surface of the water, where the partial pressure of \(\mathrm{N}_{2}\) is \(0.80 \mathrm{~atm}\)

Which of the following aqueous solutions has (a) the higher boiling point, (b) the higher freezing point, and (c) the lower vapor pressure: \(0.35 \mathrm{~m}\) \(\mathrm{CaCl}_{2}\) or \(0.90 \mathrm{~m}\) urea? Explain. Assume \(\mathrm{CaCl}_{2}\) to undergo complete dissociation.

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Aqueous solutions \(\mathrm{A}\) and \(\mathrm{B}\) both contain urea at different concentrations. On standing while exposed to air, the vapor pressure of A remains constant while that of B gradually decreases. (a) Which solution has a higher boiling point? (b) Eventually the two solutions have the same vapor pressure. Explain.

Arrange the following solutions in order of decreasing freezing point: \(0.10 \mathrm{~m} \mathrm{Na}_{3} \mathrm{PO}_{4}, 0.35 \mathrm{~m} \mathrm{NaCl}\) \(0.20 \mathrm{~m} \mathrm{MgCl}_{2}, 0.15 \mathrm{~m} \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}, 0.15 \mathrm{~m} \mathrm{CH}_{3} \mathrm{COOH}\)

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