A protein molecule, \(\mathrm{P}\), of molar mass \(\mathscr{A}\) dimerizes when it is allowed to stand in solution at room temperature. A plausible mechanism is that the protein molecule is first denatured (that is, loses its activity due to a change in overall structure) before it dimerizes: $$ \begin{array}{rlr} \mathrm{P} & \stackrel{k}{\longrightarrow} \mathrm{P}^{*}(\text { denatured }) & \text { slow } \\ 2 \mathrm{P}^{*} \longrightarrow \mathrm{P}_{2} & \text { fast } \end{array} $$ where the asterisk denotes a denatured protein molecule. Derive an expression for the average molar mass (of \(\mathrm{P}\) and \(\mathrm{P}_{2}\) ), \(, \overline{\mathscr{M}}\), in terms of the initial protein concentration \([\mathrm{P}]_{0}\) and the concentration at time \(t,\) \([\mathrm{P}]_{,}\) and \(\mathscr{A} .\) Describe how you would determine \(k\) from molar mass measurements.

Short Answer

Expert verified
The average molar mass \(\overline{\mathscr{M}}\) is \(\overline{\mathscr{M}} = \mathscr{A} + \mathscr{A}(1 - \frac{[\mathrm{P}]}{[\mathrm{P}]_0})\). The rate constant \(k\) can be determined by comparing the experimental rate of the reaction with the theoretical rate predicted by the rate law for the first step of the reaction: \(\text{rate of denaturation} = k [\mathrm{P}]\).

Step by step solution

01

Determine \(k\)

To determine the rate constant \(k\) from molar mass measurements, first measure the concentration of protein P at various times and then use these values to calculate the rate at which the protein is denatured. Knowing the initial concentration of the protein P, the rate law for the first step of the reaction can be written as: \(\text{rate of denaturation} = k [\mathrm{P}]\). As the first step is the slow (rate-determining) step, the rate of the overall reaction should also be equal to the rate of denaturation. By comparing the experimental rate of the reaction with the theoretical rate, the rate constant \(k\) can be determined.
02

Calculate the mole fraction

To find the average molar mass, we need to consider both the individual protein molecules P and the protein dimer \(P_{2}\). Compute the mole fraction of the dimer using the initial and final protein concentrations, \(x_{P} = \frac{[\mathrm{P}]}{[\mathrm{P}]_0}\) and \(x_{P_{2}} = 1 - x_{P}\). This considers that at the beginning all molecules are in the form of protein P and that over time some portion of protein P is converted into dimer \(P_{2}\).
03

Compute the average molar mass

The average molar mass \(\overline{\mathscr{M}}\) is the sum of the product of the mole fraction and molar mass of each species. Knowing that the molar mass of \(P_{2}\) is twice the molar mass of P, compute \(\overline{\mathscr{M}} = x_{P}\mathscr{A} + x_{P_{2}}2\mathscr{A} = \mathscr{A} + (2\mathscr{A}-\mathscr{A})x_{P_{2}} = \mathscr{A} + \mathscr{A}(1 - x_{P})\). This shows that the average molar mass depends on the initial concentration \([\mathrm{P}]_{0}\), the concentration at time \(t,\) \([\mathrm{P}]\), and the molar mass of the protein \(\mathscr{A}\).

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Most popular questions from this chapter

To carry out metabolism, oxygen is taken up by hemoglobin (Hb) to form oxyhemoglobin (HbO \(_{2}\) ) according to the simplified equation $$ \mathrm{Hb}(a q)+\mathrm{O}_{2}(a q) \stackrel{k}{\longrightarrow} \mathrm{HbO}_{2}(a q) $$ where the second-order rate constant is \(2.1 \times 10^{6} / M \cdot \mathrm{s}\) at \(37^{\circ} \mathrm{C}\). (The reaction is first order in \(\mathrm{Hb}\) and \(\mathrm{O}_{2}\).) For an average adult, the concentrations of \(\mathrm{Hb}\) and \(\mathrm{O}_{2}\) in the blood at the lungs are \(8.0 \times 10^{-6} \mathrm{M}\) and \(1.5 \times 10^{-6} M,\) respectively. (a) Calculate the rate of formation of \(\mathrm{HbO}_{2}\). (b) Calculate the rate of consumption of \(\mathrm{O}_{2}\). (c) The rate of formation of \(\mathrm{HbO}_{2}\) increases to \(1.4 \times 10^{-4} M / \mathrm{s}\) during exercise to meet the demand of increased metabolism rate. Assuming the \(\mathrm{Hb}\) concentration to remain the same, what must be the oxygen concentration to sustain this rate of \(\mathrm{HbO}_{2}\) formation?

How does a catalyst increase the rate of a reaction?

Chlorine oxide (ClO), which plays an important role in the depletion of ozone (see Problem 13.101 ), decays rapidly at room temperature according to the equation $$ 2 \mathrm{ClO}(g) \longrightarrow \mathrm{Cl}_{2}(g)+\mathrm{O}_{2}(g) $$ From the following data, determine the reaction order and calculate the rate constant of the reaction. $$ \begin{array}{ll} \hline \text { Time (s) } & {[\mathrm{ClO}](M)} \\ \hline 0.12 \times 10^{-3} & 8.49 \times 10^{-6} \\ 0.96 \times 10^{-3} & 7.10 \times 10^{-6} \\ 2.24 \times 10^{-3} & 5.79 \times 10^{-6} \\ 3.20 \times 10^{-3} & 5.20 \times 10^{-6} \\ 4.00 \times 10^{-3} & 4.77 \times 10^{-6} \\ \hline \end{array} $$

The rate law for the reaction \(2 \mathrm{H}_{2}(g)+2 \mathrm{NO}(g) \longrightarrow \mathrm{N}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(g)\) is rate \(=k\left[\mathrm{H}_{2}\right][\mathrm{NO}]^{2} .\) Which of the following mechanisms can be ruled out on the basis of the observed rate expression? Mechanism I $$ \begin{array}{c} \mathrm{H}_{2}+\mathrm{NO} \longrightarrow \mathrm{H}_{2} \mathrm{O}+\mathrm{N} \\ \mathrm{N}+\mathrm{NO} \longrightarrow \mathrm{N}_{2}+\mathrm{O} \\ \mathrm{O}+\mathrm{H}_{2} \longrightarrow \mathrm{H}_{2} \mathrm{O} \end{array} $$ $$ \begin{aligned} &\text { Mechanism II }\\\ &\begin{array}{l} \mathrm{H}_{2}+2 \mathrm{NO} \longrightarrow \mathrm{N}_{2} \mathrm{O}+\mathrm{H}_{2} \mathrm{O} \\ \mathrm{N}_{2} \mathrm{O}+\mathrm{H}_{2} \longrightarrow \mathrm{N}_{2}+\mathrm{H}_{2} \mathrm{O} \end{array} \end{aligned} $$ Mechanism III $$ \begin{aligned} 2 \mathrm{NO} & \rightleftharpoons \mathrm{N}_{2} \mathrm{O}_{2} \\ \mathrm{~N}_{2} \mathrm{O}_{2}+\mathrm{H}_{2} & \longrightarrow \mathrm{N}_{2} \mathrm{O}+\mathrm{H}_{2} \mathrm{O} \\ \mathrm{N}_{2} \mathrm{O}+\mathrm{H}_{2} \longrightarrow & \mathrm{N}_{2}+\mathrm{H}_{2} \mathrm{O} \end{aligned} $$

The rate constants for the first-order decomposition of an organic compound in solution are measured at several temperatures: $$ \begin{array}{cccccc} k\left(\mathrm{~s}^{-1}\right) & 0.00492 & 0.0216 & 0.0950 & 0.326 & 1.15 \\ T(\mathrm{~K}) & 278 & 288 & 298 & 308 & 318 \end{array} $$ Determine graphically the activation energy and frequency factor for the reaction.

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