Write the reaction rate expressions for the following reactions in terms of the disappearance of the reactants and the appearance of products: (a) \(2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(g)\) (b) \(4 \mathrm{NH}_{3}(g)+5 \mathrm{O}_{2}(g) \longrightarrow 4 \mathrm{NO}(g)+6 \mathrm{H}_{2} \mathrm{O}(g)\)

Short Answer

Expert verified
The rate expressions for the two reactions given are: (a) - \(\frac{1}{2}\) \(\frac{d[H2]}{dt}\) = - \(\frac{d[O2]}{dt}\) = \(\frac{1}{2}\) \(\frac{d[H2O]}{dt}\), and (b) - \(\frac{1}{4}\) \(\frac{d[NH3]}{dt}\) = - \(\frac{1}{5}\) \(\frac{d[O2]}{dt}\) = \(\frac{1}{4}\) \(\frac{d[NO]}{dt}\) = \(\frac{1}{6}\) \(\frac{d[H2O]}{dt}\).

Step by step solution

01

Write the reaction rate for reaction (a)

For reaction (a), the stoichiometric relationship is 2H2 + O2 -> 2H2O. For reaction rate, it is assumed that the concentration of reactants decreases with time while the concentration of products increases. Therefore, the rate can be written as: - \(\frac{1}{2}\) \(\frac{d[H2]}{dt}\) = - \(\frac{d[O2]}{dt}\) = \(\frac{1}{2}\) \(\frac{d[H2O]}{dt}\). Note: The negative sign shows the decrease in the concentration of reactants and the coefficients are taken into account.
02

Write the reaction rate for reaction (b)

For the second reaction (b), the stoichiometric relationship is 4NH3 + 5O2 -> 4NO + 6H2O. Applying the same approach, the rate of the reaction would be: - \(\frac{1}{4}\) \(\frac{d[NH3]}{dt}\) = - \(\frac{1}{5}\) \(\frac{d[O2]}{dt}\) = \(\frac{1}{4}\) \(\frac{d[NO]}{dt}\) = \(\frac{1}{6}\) \(\frac{d[H2O]}{dt}\). The stoichiometric coefficients are used to normalize the changes in concentration.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Kinetics
Understanding chemical kinetics is crucial for grasping how reaction rates are influenced by various factors. Chemical kinetics delves into the speed or rate at which chemical reactions occur and the mechanisms by which reactions proceed.

Within this field, it's vital to consider the energy needed to initiate a reaction, known as activation energy, and how temperature, catalysts, and concentration of reactants can affect the reaction rate. The rate of a reaction can tell us a lot about the mechanism, allowing chemists to optimize conditions for industrial processes or to understand natural phenomena. To quantify these rates, we use the concept of the reaction rate expression, which involves calculus to measure the change in concentration of reactants or products over time.
Stoichiometry
Stoichiometry is the mathematical relationship between the amounts of reactants and products in a chemical reaction. It's based on the law of conservation of mass, which states that in a chemical reaction, the total mass of the reactants must equal the total mass of the products.

Balancing Equations

At the core of stoichiometry is the balanced chemical equation, which serves as a recipe for the reaction. To balance an equation, we must ensure that the same number of atoms of each element are present on both sides of the reaction. This balance is reflected in the stoichiometric coefficients, which are the numbers placed in front of the chemical formulas.

Relation to Reaction Rates

These coefficients also play a central role in the calculation of reaction rates, as seen in the given exercise. They tell us the proportional rates at which compounds react and form products. For instance, the coefficient '2' in front of \( \mathrm{H}_{2} \) in reaction (a) means that two moles of hydrogen gas are consumed for every mole of oxygen gas used to form water.
Reaction Rates
Reaction rates are a fundamental part of understanding chemical reactions. They indicate how quickly reactants are transformed into products over a certain period.

A reaction's rate can be expressed in terms of the rate of disappearance of reactants or the rate of appearance of products. This rate is generally given as a negative value for reactants because they are being consumed, and as a positive value for products because they are being created.

When determining the reaction rate expression, the stoichiometric coefficients must be taken into account to ensure the rate is consistent with the reaction stoichiometry. In the solutions provided for reactions (a) and (b), the reaction rate expressions illustrate how the coefficients from the balanced equations are inverted and applied to each reactant and product, normalizing the rates of change. This approach highlights the stoichiometrically balanced view of the reaction, linking the disappearance of reactants to the appearance of products in a quantitative manner.

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Most popular questions from this chapter

Sketch a potential energy versus reaction progress plot for the following reactions: $$ \begin{array}{l} \text { (a) } \mathrm{S}(s)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{SO}_{2}(g) \quad \Delta H^{\circ}= \\ \quad-296 \mathrm{~kJ} / \mathrm{mol} \\ \text { (b) } \mathrm{Cl}_{2}(g) \longrightarrow \mathrm{Cl}(g)+\mathrm{Cl}(g) \Delta H^{\circ}=243 \mathrm{~kJ} / \mathrm{mol} \end{array} $$

The reaction \(\mathrm{H}+\mathrm{H}_{2} \longrightarrow \mathrm{H}_{2}+\mathrm{H}\) has been studied for many years. Sketch a potential energy versus reaction progress diagram for this reaction.

A factory that specializes in the refinement of transition metals such as titanium was on fire. The firefighters were advised not to douse the fire with water. Why?

The bromination of acetone is acid-catalyzed: \(\mathrm{CH}_{3} \mathrm{COCH}_{3}+\mathrm{Br}_{2} \frac{\mathrm{H}^{+}}{\text {cually }} \mathrm{CH}_{3} \mathrm{COCH}_{2} \mathrm{Br}+\mathrm{H}^{+}+\mathrm{Br}^{-}\) The rate of disappearance of bromine was measured for several different concentrations of acetone, bromine, and \(\mathrm{H}^{+}\) ions at a certain temperature: $$ \begin{array}{lclll} \hline & &{\text { Rate of }} \\ & & & & \text { Disappearance } \\ & {\left[\mathrm{CH}_{3} \mathrm{COCH}_{3}\right]} & {\left[\mathrm{Br}_{2}\right]} & {\left[\mathrm{H}^{+}\right]} & \text {of } \mathrm{Br}_{2}(M / \mathrm{s}) \\ \hline(1) & 0.30 & 0.050 & 0.050 & 5.7 \times 10^{-5} \\ (2) & 0.30 & 0.10 & 0.050 & 5.7 \times 10^{-5} \\ (3) & 0.30 & 0.050 & 0.20 & 1.2 \times 10^{-4} \\ (4) & 0.40 & 0.050 & 0.20 & 3.1 \times 10^{-4} \\ (5) & 0.40 & 0.050 & 0.050 & 7.6 \times 10^{-5} \\ \hline \end{array} $$ (a) What is the rate law for the reaction? (b) Determine the rate constant. (c) The following mechanism has been proposed for the reaction: Show that the rate law deduced from the mechanism is consistent with that shown in (a).

Write the Arrhenius equation and define all terms.

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