Chapter 14: Problem 50
Use Le Châtelier's principle to explain why the equilibrium vapor pressure of a liquid increases with increasing temperature.
Chapter 14: Problem 50
Use Le Châtelier's principle to explain why the equilibrium vapor pressure of a liquid increases with increasing temperature.
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Get started for freeThe equilibrium constant \(K_{P}\) for the reaction $$2 \mathrm{H}_{2} \mathrm{O}(g) \rightleftharpoons 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g)$$ is \(2 \times 10^{-42}\) at \(25^{\circ} \mathrm{C}\). (a) What is \(K_{\mathrm{c}}\) for the reaction at the same temperature? (b) The very small value of \(K_{P}\) (and \(K_{\mathrm{c}}\) ) indicates that the reaction overwhelmingly favors the formation of water molecules. Explain why, despite this fact, a mixture of hydrogen and oxygen gases can be kept at room temperature without any change.
Consider this equilibrium reaction in a closed container: $$\mathrm{CaCO}_{3}(s) \rightleftharpoons \mathrm{CaO}(s)+\mathrm{CO}_{2}(g)$$ What will happen if the following occurs? (a) The volume is increased. (b) Some \(\mathrm{CaO}\) is added to the mixture. (c) Some \(\mathrm{CaCO}_{3}\) is removed. (d) Some \(\mathrm{CO}_{2}\) is added to the mixture. (e) A few drops of a \(\mathrm{NaOH}\) solution are added to the mixture. (f) A few drops of a \(\mathrm{HCl}\) solution are added to the mixture (ignore the reaction between \(\mathrm{CO}_{2}\) and water). (g) Temperature is increased.
The "boat" form and "chair" form of cyclohexane \(\left(\mathrm{C}_{6} \mathrm{H}_{12}\right)\) interconverts as shown here: In this representation, the \(\mathrm{H}\) atoms are omitted and a \(\mathrm{C}\) atom is assumed to be at each intersection of two lines (bonds). The conversion is first order in each direction. The activation energy for the chair \(\longrightarrow\) boat conversion is \(41 \mathrm{~kJ} / \mathrm{mol} .\) If the frequency factor is \(1.0 \times 10^{12} \mathrm{~s}^{-1},\) what is \(k_{1}\) at \(298 \mathrm{~K} ?\) The equilibrium constant \(K_{\mathrm{c}}\) for the reaction is \(9.83 \times 10^{3}\) at \(298 \mathrm{~K}\).
The following equilibrium constants have been determined for hydrosulfuric acid at \(25^{\circ} \mathrm{C}\) $$\begin{array}{l}\mathrm{H}_{2} \mathrm{~S}(a q) \rightleftharpoons \mathrm{H}^{+}(a q)+\mathrm{HS}^{-}(a q) \\\\\qquad \begin{aligned}K_{\mathrm{c}}^{\prime} &=9.5 \times 10^{-8} \\\\\mathrm{HS}^{-}(a q) \Longrightarrow \mathrm{H}^{+}(a q)+\mathrm{S}^{2-}(a q) \\\K_{\mathrm{c}}^{\prime \prime}=1.0 \times 10^{-19}\end{aligned}\end{array}$$ Calculate the equilibrium constant for the following reaction at the same temperature: $$\mathrm{H}_{2} \mathrm{~S}(a q) \rightleftharpoons 2 \mathrm{H}^{+}(a q)+\mathrm{S}^{2-}(a q)$$
What do the symbols \(K_{\mathrm{c}}\) and \(K_{P}\) represent?
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