A sealed glass bulb contains a mixture of \(\mathrm{NO}_{2}\) and \(\mathrm{N}_{2} \mathrm{O}_{4}\) gases. Describe what happens to the following properties of the gases when the bulb is heated from \(20^{\circ} \mathrm{C}\) to \(40^{\circ} \mathrm{C}:\) (a) color, (b) pressure, (c) average molar mass, (d) degree of dissociation (from \(\mathrm{N}_{2} \mathrm{O}_{4}\) to \(\mathrm{NO}_{2}\) ), (e) density. Assume that volume remains constant. (Hint: \(\mathrm{NO}_{2}\) is a brown gas; \(\mathrm{N}_{2} \mathrm{O}_{4}\) is colorless.)

Short Answer

Expert verified
When the bulb is heated from 20°C to 40°C: (a) the color changes from colorless to brown due to the increase in NO2, (b) the pressure increases due to the increase in number of gas molecules, (c) the average molar mass decreases due to the increased proportion of NO2 with a lower molar mass, (d) the degree of dissociation increases due to more N2O4 dissociating into NO2, (e) the density increases due to the increased number of molecules and decreased molar mass.

Step by step solution

01

Color

At room temperature, N2O4 is a colorless gas while NO2 is a brown gas. As the temperature of the bulb is increased from 20°C to 40°C, N2O4 tends to dissociate into NO2, contributing to an increase in the concentration of brown NO2 gas. Hence, the bulb's color turns from colorless to brown.
02

Pressure

The equilibrium shift causes the number of gas molecules to increase (since two NO2 molecules are produced from each N2O4 molecule). As the number of molecules increases in a sealed bulb (fixed volume), the pressure will also increase according to the ideal gas law.
03

Average Molar Mass

At 20°C, there is a mixture of N2O4 (molar mass 92) and NO2 (molar mass 46). As the temperature increases, N2O4 dissociates into NO2, increasing the mole fraction of NO2 which has a lower molar mass. Hence, the average molar mass of the gases in the bulb decreases.
04

Degree of Dissociation

The degree of dissociation represents how much of N2O4 dissociates to form NO2. As the temperature increases from 20°C to 40°C, more N2O4 molecules will dissociate to form NO2. Hence, the degree of dissociation increases.
05

Density

Density is mass per unit volume. As the average molar mass decreases and the pressure increases, the density of the gas mixture also increases due to the increase in the number of molecules (more NO2 from dissociation of N2O4) in the sealed bulb (fixed volume).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Le Chatelier's Principle
Le Chatelier's Principle predicts how a chemical system at equilibrium reacts to disturbances or external changes. It states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium moves to counteract the change. When the glass bulb in our exercise is heated, the principle foresees that the system will adjust. In this case, the increased temperature causes the equilibrium to shift so that the exothermic reaction, the formation of N2O4 from NO2, is reduced, and the endothermic reaction, the dissociation of N2O4 to NO2, is favored. This response to an external temperature change results in a higher concentration of brown NO2 gas, leading to the observed color change in the bulb.

Understanding Le Chatelier's Principle helps students predict the outcome of altering variables such as temperature, pressure, or concentration in a chemical reaction at equilibrium. This also informs us that heating the bulb not only affects the color but also has implications for pressure, molecular properties, and gas density, which are interconnected through the behavior of the gases under equilibrium.
Ideal Gas Law
The ideal gas law is a critical equation in chemistry and physics, represented as PV=nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature. This equation describes the state of a hypothetical 'ideal' gas, and although real gases do not always behave perfectly, the ideal gas law provides a good approximation under many conditions.

Applying the ideal gas law to the problem at hand, when the temperature (T) inside the bulb increases, and since the volume (V) remains constant, either the pressure (P) must increase, or the number of moles (n) must decrease. In our exercise, as the temperature rises, the dissociation of N2O4 into NO2 increases the number of gas molecules, thereby increasing the pressure inside the sealed bulb given that the volume remains constant.
Molecular Dissociation
Molecular dissociation occurs when molecules break apart into smaller molecules or atoms, which is common in reversible reactions like the one between NO2 and N2O4. The forward reaction is the association of NO2 molecules to form N2O4, while the reverse reaction is the dissociation of N2O4 to form NO2. When the equilibrium between these two is disturbed by a temperature change, the balance between association and dissociation shifts.

In our scenario, heating promotes the endothermic dissociation of N2O4 into NO2, leading to an increase in the degree of dissociation as more N2O4 is broken down. This concept is crucial to understand as it not only explains the changes in color and pressure but is also directly related to changes in average molar mass and density.
Gas Density
Gas density is a measure of mass per unit volume of a gas. It can be influenced by temperature, pressure, and molecular weight of the gas particles. In the context of the exercise, the density change of the gas mixture when heated can be counterintuitive. As N2O4 dissociates into NO2, the average molar mass decreases because we now have a higher proportion of the lighter NO2 molecules.

However, what may seem unexpected is that the density of the gas mixture increases, despite the lower average molar mass. This increase in density can be attributed to the rise in pressure within the fixed volume of the bulb - a result of the increased number of NO2 molecules produced from the dissociation of N2O4. The combined understanding of temperature effects on chemical equilibrium, and the use of the ideal gas law, helps to fully grasp this sophisticated behavior of gas density in response to temperature changes.

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Most popular questions from this chapter

Consider the reaction between \(\mathrm{NO}_{2}\) and \(\mathrm{N}_{2} \mathrm{O}_{4}\) in a closed container: $$\mathrm{N}_{2} \mathrm{O}_{4}(g) \rightleftharpoons 2 \mathrm{NO}_{2}(g)$$ Initially, 1 mole of \(\mathrm{N}_{2} \mathrm{O}_{4}\) is present. At equilibrium, \(\alpha\) mole of \(\mathrm{N}_{2} \mathrm{O}_{4}\) has dissociated to form \(\mathrm{NO}_{2}\). (a) Derive an expression for \(K_{P}\) in terms of \(\alpha\) and \(P\), the total pressure. (b) How does the expression in (a) help you predict the shift in equilibrium due to an increase in \(P ?\) Does your prediction agree with Le Châtelier's principle?

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