Calculate the concentration of \(\mathrm{H}^{+}\) ions in a \(0.62 M\) NaOH solution.

Short Answer

Expert verified
The concentration of \(H^{+}\) ions in the 0.62 M NaOH solution is approximately \(1.61 \times 10^{-14} M\).

Step by step solution

01

Identify the Ionization Process

Sodium Hydroxide (NaOH) is a strong base that completely ionizes in water to sodium ions (Na+) and hydroxide ions (OH-). Hence, the concentration of OH- ions in the solution will be the same as that of NaOH which is \(0.62 M\).
02

Utilize the Relationship Between H+ and OH- Ions

The product of the concentrations of the H+ and OH- ions is equal to the ion product constant for water (\(K_w\)) which is \(1.0 \times 10^{-14}\) at 25 degrees Celsius. The relationship is given as \([H+][OH-] = K_w\). Hence, we can calculate the concentration of H+ ions using: \([H+] = \frac{K_w}{[OH-]}\)
03

Calculate the Concentration of H+ ions

Substituting the values into the equation, the concentration of H+ ions can be calculated as: \([H+] = \frac{1.0 \times 10^{-14}}{0.62}\)

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Most popular questions from this chapter

A \(0.400 M\) formic acid (HCOOH) solution freezes at \(-0.758^{\circ} \mathrm{C}\). Calculate the \(K_{\mathrm{a}}\) of the acid at that temperature. (Hint: Assume that molarity is equal to molality. Carry your calculations to three significant figures and round off to two for \(K_{\mathrm{a}}\).)

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