Calculate the \(\mathrm{pH}\) of each of the following solutions: (a) \(0.0010 \mathrm{MHCl}\), (b) \(0.76 M\) KOH.

Short Answer

Expert verified
The pH of the \(0.0010 \mathrm{MHCl}\) solution is 3.0 and the pH of the \(0.76 M \mathrm{KOH}\) solution is 13.12.

Step by step solution

01

Calculate pH of the HCl solution

Given the molarity (M) of the HCl solution as 0.0010 M. Because HCl is a strong acid, it fully dissociates in water to give H+ ions, so the concentration of H+ ions will be the same as the molarity of the solution. Therefore, the pH of the solution can be calculated using the formula: \(\mathrm{pH} = - \log[\mathrm{H^+}]\). Substituting the known H+ concentration, the pH of the solution is calculated as \( \mathrm{pH} = - \log(0.0010) = 3.0 \).
02

Calculate pOH of the KOH solution

Given the molarity (M) of the KOH solution as 0.76 M. KOH is a strong base which fully dissociates in water to give OH- ions. So the concentration of OH- ions is the same as the molarity of the KOH solution. The pOH of the solution can be calculated using the formula: \(\mathrm{pOH} = - \log[\mathrm{OH^-}]\). By substituting the known OH- concentration: \(\mathrm{pOH} = - \log(0.76) = - \log(7.6 \times 10^{-1}) = - (-0.88) = 0.88\).
03

Calculate pH of the KOH solution

The pH can be found using the relation \( \mathrm{pH} = 14 - \mathrm{pOH} \). Substituting the known pOH: \(\mathrm{pH} = 14 - 0.88 = 13.12 \).

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