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Chapter 15: Problem 24

Calculate the number of moles of \(\mathrm{KOH}\) in \(5.50 \mathrm{~mL}\) of a \(0.360 \mathrm{M}\) KOH solution. What is the \(\mathrm{pOH}\) of the solution?

Short Answer

Expert verified
The number of moles of KOH is \(0.00198 \ \mathrm{moles}\), and the pOH of the solution is 0.44.

Step by step solution

01

Convert volume to liters

Since molarity is defined as moles per liter, the volume should be converted from milliliters to liters. This can be done by the division of the volume by 1000 which will give \(5.50 \ \mathrm{mL} \ = \ 0.00550 \ \mathrm{L}\).
02

Calculate the number of moles of KOH

The number of moles can be calculated using the formula of molarity = moles/volume. Therefore, Moles = Molarity * Volume. Substituting the given values, we get moles of KOH = \(0.360 \ \mathrm{M} \ * \ 0.00550 \ \mathrm{L}\) = \(0.00198 \ \mathrm{mole}\).
03

Calculate the pOH of the solution

For KOH, a strong base, it will disassociate completely in the solution. Thus, the concentration of OH- ions will be equal to the molarity of KOH which is 0.360 M. Now, pOH is calculated by the formula -log[OH-]. Thus, pOH = \(- \log(0.360) = 0.44\)

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