Explain what is meant by the strength of an acid.

Short Answer

Expert verified
The strength of an acid refers to its ability to donate protons (H+) in a solution. Factors that determine acid strength include its dissociation constant (\(K_a\)), with a higher \(K_a\) indicating a stronger acid. For example, Hydrochloric Acid (HCl) is a strong acid as it ionizes completely in water, whereas Acetic acid (CH3COOH) is a weak acid as it only partially ionizes in water.

Step by step solution

01

Conceptual Definition

The strength of an acid refers to its ability to donate protons (H+) in a solution. An acid that can readily donate protons and hence ionize completely in a solution is referred to as a strong acid. Conversely, an acid that does not ionize completely and thus donates protons less readily is known as a weak acid.
02

Factors That Determine Acid Strength

The strength of an acid is determined by its dissociation constant (\(K_a\)), which measures the extent of ionization of the acid in water. A higher \(K_a\) value indicates a stronger acid.
03

Example of Acid Strength

An example can make this clearer. Hydrochloric Acid (HCl) is a strong acid because it ionizes completely in water, donating all its protons to form Hydronium ions (\(H_3O^+\)) and Chloride ions (\(Cl^-\)). On the other hand, Acetic acid (CH3COOH), a weak acid, only partially ionizes in water, releasing fewer protons.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free