Write the solubility product expression for the ionic compound \(\mathrm{A}_{x} \mathrm{~B}_{y}\)

Short Answer

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The solubility product expression for the ionic compound AxBy can be given by \( K_{sp} = [A^{n+}]^{x} \cdot [B^{m-}]^{y} \)

Step by step solution

01

Writing the Dissolution Equation

First, write down the dissolution equation of the ionic compound AxBy. The compound dissociates into its constituent ions in a solution. In this case, the equation will be: \( AxBy \leftrightarrow xA^{n+} + yB^{m-} \). The arrows indicate that the reaction is in equilibrium.
02

Writing the Solubility Product Expression

The solubility product expression, denoted by \( K_{sp} \), is the product of concentrations of its constituent ions, each raised to the power equal to its stoichiometric coefficient. Therefore, we can write the \( K_{sp} \) for the given compound as: \( K_{sp} = [A^{n+}]^{x} \cdot [B^{m-}]^{y} \), where [A] and [B] are the concentrations of the ions A and B respectively in the solution, and x and y are their stoichiometric coefficients.

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