Comment on whether \(\mathrm{F}_{2}\) will become a stronger oxidizing agent with increasing \(\mathrm{H}^{+}\) concentration.

Short Answer

Expert verified
According to the provided information, increasing the \( \mathrm{H}^{+} \) concentration will not make \(\mathrm{F}_{2}\) a stronger oxidizing agent.

Step by step solution

01

Understand the relevant reaction

Consider the following half-reaction: \(\mathrm{F}_{2} + 2e^- \rightarrow 2\mathrm{F}^{-}\). Here, Fluorine is acting as an oxidizing agent because it is accepting electrons.
02

Determine the effect of \( \mathrm{H}^{+} \) ions

In this reaction, the concentration of \( \mathrm{H}^{+} \) ions does not have a direct role. Therefore, changing this concentration will not directly influence the ability of Fluorine to act as an oxidizing agent.
03

Reason from the perspective of Le Chatelier's principle

However, if other reactions are involved where \( \mathrm{H}^{+} \) ions are implicated, the situation might change according to Le Chatelier’s principle (which states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium shifts to counteract the change). For this specific query though, since no such other reactions are mentioned, it can be concluded as per the given information that an increase in \( \mathrm{H}^{+} \) concentration will not make \(\mathrm{F}_{2}\) a stronger oxidizing agent.

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