Which of the following reagents can oxidize \(\mathrm{H}_{2} \mathrm{O}\) to \(\mathrm{O}_{2}(g)\) under standard-state conditions: \(\mathrm{H}^{+}(a q), \mathrm{Cl}^{-}(a q)\) \(\mathrm{Cl}_{2}(g), \mathrm{Cu}^{2+}(a q), \mathrm{Pb}^{2+}(a q), \mathrm{MnO}_{4}^{-}(a q)\) (in acid)?

Short Answer

Expert verified
Under standard conditions, only \(\mathrm{MnO}_{4}^{-}(a q)\) in an acid solution can oxidize \(\mathrm{H}_{2} \mathrm{O}\) to \(\mathrm{O}_{2}(g).\

Step by step solution

01

Understanding oxidation and standard-state conditions

Oxidation is a chemical process where a molecule, atom or ion loses electrons. Standard-state conditions are set conditions where these reactions are usually measured, including a pressure of 1 bar and room temperature. The oxidizing agent or the reagent oxidizes \(\mathrm{H}_{2} \mathrm{O}\) by accepting its electrons and itself gets reduced.
02

Examining each reagent

We need to examine each reagent on the basis of its ability to be reduced, i.e., its ability to gain electrons.
03

Evaluating $\mathrm{H}^{+}(a q)$

\(\mathrm{H}^{+}(a q)\) ions that are already at a maximum positive oxidation state (+1) can't be oxidized any further.
04

Evaluating $\mathrm{Cl}^{-}(a q)$

\(\mathrm{Cl}^{-}(a q)\) ions are at maximum negative oxidation state (-1) and aren't reduced any further. So, it can't act as an oxidizing agent to generate oxygen gas.
05

Evaluating $\mathrm{Cl}_{2}(g)$

\(\mathrm{Cl}_{2}(g)\) is a very strong oxidizing agent that can definitely oxidize water but it doesn't do it under standard conditions.
06

Evaluating $\mathrm{Cu}^{2+}(a q)$

\(\mathrm{Cu}^{2+}(a q)\) ions are already at a maximum positive oxidation state and can't be oxidized any further.
07

Evaluating $\mathrm{Pb}^{2+}(a q)$

Though \(\mathrm{Pb}^{2+}(a q)\) can further be reduced to \(\mathrm{Pb}^{0}\), it does not have the tendency to do so. So, it's not a correct choice.
08

Evaluating $\mathrm{MnO}_{4}^{-}(a q)$ (in acid)

Under acidic conditions, $\mathrm{MnO}_{4}^{-}(a q)$ can be reduced from an oxidation state of +7 to +2. Hence, it can act as an oxidizing agent, accepting electrons from water to produce oxygen gas.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard-State Conditions
Understanding reactions in chemistry involves getting familiar with standard-state conditions, which provide a reference point for scientists to characterize substances and reactions. These conditions refer to a set temperature of 25°C (298.15K), a pressure of 1 bar, and concentrations of 1 mole per liter for substances in solution. It's under these circumstances that reagents like gases, ions, and elements are often described and their properties tabulated. For example, in redox reactions, the ability of a substance to act as an oxidizing or reducing agent is measured under standard-state conditions to ensure consistency.

Under these standardized conditions, chemists can confidently compare the tendencies of various substances to lose or gain electrons, which is the fundamental process in oxidation-reduction reactions. In educational settings, these conditions help students understand the general behavior of elements and compounds in the context of their reactions without the added complexity of variable external factors.
Oxidation and Reduction
The concepts of oxidation and reduction are central to understanding redox reactions. Oxidation is the process by which an atom, molecule, or ion loses electrons. Conversely, reduction involves the gain of electrons. These two processes go hand in hand – for every oxidation process, there is a corresponding reduction reaction happening simultaneously, hence the term 'redox' reaction. Understanding this electron transfer is crucial to grasping many chemical phenomena.

In a redox reaction, the entity that receives electrons and is reduced is called the oxidizing agent, and the one that loses electrons and is oxidized is the reducing agent. The concepts are intertwined – an oxidizing agent gets reduced during the reaction, whereas a reducing agent becomes oxidized. Oxidation can also be thought of in terms of oxidation states: an increase in oxidation state signifies oxidation, while a decrease indicates reduction. This approach helps in analyzing and balancing redox equations, a fundamental skill in chemistry.
Reagents Analysis
The analysis of reagents in redox reactions involves looking at their ability to act as oxidizing or reducing agents. Evaluating the effectiveness of a reagent, such as whether a particular compound can oxidize water to oxygen gas, requires an understanding of the reagent's oxidation state and its potential changes in the context of a reaction.

Each reagent must be examined for its ability to gain electrons, and thus, its capacity to be reduced. If a reagent is already at its maximum oxidation state, it cannot accept more electrons and therefore, cannot act as an oxidizing agent. Similarly, if a reagent is at its lowest oxidation state, it is unlikely to lose electrons and act as a reducing agent. To ascertain a substance's capability to participate in redox processes, chemists refer to standard electrode potentials, which are measured under standard-state conditions. These potentials enable the prediction of whether a given substance will undergo oxidation or reduction and thereby determine its viability as an oxidizing or reducing agent in a particular reaction.

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Most popular questions from this chapter

Oxalic acid \(\left(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\right)\) is present in many plants and vegetables. (a) Balance the following equation in acid solution: $$\mathrm{MnO}_{4}^{-}+\mathrm{C}_{2} \mathrm{O}_{4}^{2-} \longrightarrow \mathrm{Mn}^{2+}+\mathrm{CO}_{2}$$ (b) If a 1.00-g sample of \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\) requires \(24.0 \mathrm{~mL}\) of \(0.0100 \mathrm{M} \mathrm{KMnO}_{4}\) solution to reach the equivalence point, what is the percent by mass of \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\) in the sample?

For each of the following redox reactions, (i) write the half-reactions, (ii) write a balanced equation for the whole reaction, (iii) determine in which direction the reaction will proceed spontaneously under standard-state conditions: (a) \(\mathrm{H}_{2}(g)+\mathrm{Ni}^{2+}(a q) \longrightarrow \mathrm{H}^{+}(a q)+\mathrm{Ni}(s)\) (b) \(\mathrm{MnO}_{4}^{-}(a q)+\mathrm{Cl}^{-}(a q) \longrightarrow\) \(\quad \mathrm{Mn}^{2+}(a q)+\mathrm{Cl}_{2}(g)\) (in acid solution) \(\begin{array}{ll}\text { (c) } \mathrm{Cr}(s)+\mathrm{Zn}^{2+}(a q) & \longrightarrow \mathrm{Cr}^{3+}(a q)+\mathrm{Zn}(s)\end{array}\)

The \(\mathrm{SO}_{2}\) present in air is mainly responsible for the phenomenon of acid rain. The concentration of \(\mathrm{SO}_{2}\) can be determined by titrating against a standard permanganate solution as follows: \(5 \mathrm{SO}_{2}+2 \mathrm{MnO}_{4}^{-}+2 \mathrm{H}_{2} \mathrm{O} \longrightarrow \overrightarrow{5 \mathrm{SO}_{4}^{2-}+2 \mathrm{Mn}^{2+}+4 \mathrm{H}^{+}}\) Calculate the number of grams of \(\mathrm{SO}_{2}\) in a sample of air if \(7.37 \mathrm{~mL}\) of \(0.00800 \mathrm{M} \mathrm{KMnO}_{4}\) solution are required for the titration.

Fluorine \(\left(\mathrm{F}_{2}\right)\) is obtained by the electrolysis of liquid hydrogen fluoride (HF) containing potassium fluoride (KF). (a) Write the half-cell reactions and the overall reaction for the process. (b) What is the purpose of KF? (c) Calculate the volume of \(\mathrm{F}_{2}\) (in liters) collected at \(24.0^{\circ} \mathrm{C}\) and 1.2 atm after electrolyzing the solution for \(15 \mathrm{~h}\) at a current of 502 A.

Galvanized iron" is steel sheet that has been coated with zinc; "tin" cans are made of steel sheet coated with tin. Discuss the functions of these coatings and the electrochemistry of the corrosion reactions that occur if an electrolyte contacts the scratched surface of a galvanized iron sheet or a tin can.

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