Chapter 18: Problem 18
Which species in each pair is a better reducing agent under standard-state conditions: (a) Na or Li? (b) \(\mathrm{H}_{2}\) or \(\mathrm{I}_{2} ?(\mathrm{c}) \mathrm{Fe}^{2+}\) or \(\mathrm{Ag} ?\) (d) \(\mathrm{Br}^{-}\) or \(\mathrm{Co}^{2+} ?\)
Short Answer
Expert verified
The better reducing agents are Li, \(H_2\), \(\mathrm{Fe^{2+}}\), and \(\mathrm{Co^{2+}}\).
Step by step solution
01
Interpretation of the Reducing Agent
The species that acts as a reducing agent is the one that has a more negative (or less) standard reduction potential. Find the standard reduction potentials of the species from a table of standard reduction potentials.
02
Comparing the Reduction Potentials (a) Na or Li
From the standard reduction potential table, the reduction potentials are: \n\(E^°\) for Na \(+\( e^- \to Na = -2.71 V\) and \(E^°\) for Li \(+ e^- \to Li = -3.04V\). Since Li has the more negative reduction potential, Li is the better reducing agent.
03
Comparing the Reduction Potentials (b) \(\mathrm{H}_{2}\) or \(\mathrm{I}_{2}\)
From the standard reduction potential table, the reduction potentials are: \n\(E^°\) for \(\mathrm{H_2 + 2e^- \to 2H^{-} = 0 V\) and \(E^°\) for \(\mathrm{I_2 + 2e^- \to 2I^{-} = 0.54V\). Since \(H_2\) has the less positive reduction potential, \(H_2\) is the better reducing agent.
04
Comparing the Reduction Potentials (c) \(\mathrm{Fe}^{2+}\) or \(\mathrm{Ag}\)
From the standard reduction potential table, the reduction potentials are: \n\(E^°\) for \(\mathrm{Fe^{3+} + e^- \to Fe^{2+}} = +0.77V\) and \(E^°\) for \(\mathrm{Ag^{+} + e^- \to Ag} = +0.80V\). As both species are in reduced forms and \(\mathrm{Fe^{2+}}\) has the lower reduction potential, \(\mathrm{Fe^{2+}}\) is the better reducing agent.
05
Comparing the Reduction Potentials (d) \(\mathrm{Br^-}\) or \(\mathrm{Co^{2+}}\)
From the standard reduction potential table, the reduction potentials are: \n\(E^°\) for \(\mathrm{Br_2 + 2e^- \to 2Br^-} = 1.07V\) and \(E^°\) for \(\mathrm{Co^{3+} + e^- \to Co^{2+}} = 1.92V\). As both species are in reduced forms and \(\mathrm{Co^{2+}}\) has the lower reduction potential, \(\mathrm{Co^{2+}}\) is the better reducing agent.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Standard Reduction Potential
Understanding the standard reduction potential is vital when studying redox reactions and determining the strength of reducing agents. In simple terms, the standard reduction potential, represented by the symbol \( E^° \), is a measure of the tendency of a chemical species to acquire electrons and thereby be reduced. It is usually measured in volts (V) and is determined under standard conditions, which include a concentration of 1 molar, pressure of 1 atmosphere, and a temperature of 25°C (298 K).
When comparing two species, the one with a more negative \( E^° \) value is generally a better reducing agent because it more readily donates electrons to other substances. This is the principle applied in the textbook exercise when choosing the better reducing agent between species like Na and Li or \( H_2 \) and \( I_2 \). It’s crucial for students to know how to consult a standard reduction potential table and interpret the values to determine the capabilities of reducing agents in an electrochemical context.
When comparing two species, the one with a more negative \( E^° \) value is generally a better reducing agent because it more readily donates electrons to other substances. This is the principle applied in the textbook exercise when choosing the better reducing agent between species like Na and Li or \( H_2 \) and \( I_2 \). It’s crucial for students to know how to consult a standard reduction potential table and interpret the values to determine the capabilities of reducing agents in an electrochemical context.
Electrochemical Series
The electrochemical series is like a leaderboard that ranks chemical elements and compounds based on their standard reduction potentials. Elements at the top of the series have greater tendencies to lose electrons and are consequently better oxidizing agents. On the other hand, elements toward the bottom of the series are better at gaining electrons and thus make stronger reducing agents.
Understanding the Series:
Understanding the Series:
- Elements with more positive standard reduction potentials are typically found at the top.
- Elements with more negative standard reduction potentials are found toward the bottom.
- The series can predict spontaneity of redox reactions—those with a positive potential are generally spontaneous.
Redox Reactions
Redox reactions are the bread and butter of electrochemistry, encompassing all chemical reactions where there is a change in oxidation state due to a transfer of electrons between two species. Redox is a portmanteau for 'reduction-oxidation'. In every redox reaction, there is both an oxidizing agent and a reducing agent.
Key Points of Redox Reactions:
Key Points of Redox Reactions:
- The oxidizing agent gains electrons and is reduced in the process.
- The reducing agent loses electrons and is oxidized as it does so.
- Such reactions are fundamental to many processes, including metabolism and energy production, as well as industrial applications like corrosion and battery function.
- An element’s ability to function as a reducing agent can be analyzed using its standard reduction potential, as shown in the exercise solutions.