In the chapter, we learned to calculate the nuclear binding energy, which
pertains to the stability of a particular nucleus. It is also possible to
estimate the binding energy of a single nucleon (neutron or proton) to the
remainder of the nucleus. (a) From the following nuclear equation and nuclear
masses, calculate the binding energy of a single neutron:
$${ }_{7}^{14} \mathrm{~N} \longrightarrow{ }_{7}^{13} \mathrm{~N}+{ }_{0}^{1}
\mathrm{n}$$
(Useful information: \({ }_{7}^{14} \mathrm{~N}: 14.003074 \mathrm{amu} ;{
}_{7}^{13} \mathrm{~N}:\)
13.005738 amu; \({ }_{0}^{1} \mathrm{n}: 1.00866\) amu. \()\) (b) By a similar
procedure, we can calculate the binding energy of a single proton according to
the equation
$${ }_{7}^{14} \mathrm{~N} \longrightarrow{ }_{6}^{13} \mathrm{C}+{ }_{1}^{1}
\mathrm{p}$$
(Useful information: \({ }_{6}^{13} \mathrm{C}: 13.003355 \mathrm{amu} ;{
}_{1}^{1} \mathrm{p}:\)
1.00794 amu.) Comment on your results.