Pair the following species that contain the same number of electrons: \(\mathrm{Ar}, \mathrm{Sn}^{4+}, \mathrm{F}^{-}, \mathrm{Fe}^{3+}, \mathrm{P}^{3-}, \mathrm{V}, \mathrm{Ag}^{+}, \mathrm{N}^{3-}\)

Short Answer

Expert verified
The pairs are: Argon (Ar) and Phosphorus (P^{3-}), Tin Sn(4+) and Silver Ag(+), Fluorine (F-) and Nitrogen (N^{3-}), Iron (Fe^{3+}) and Vanadium (V).

Step by step solution

01

Determine the number of protons

The atomic number, also known as the number of protons, of an atom can be found in the periodic table. Therefore, for each given species, find out their atomic numbers. Argon (Ar) has 18 protons, Tin SN(4+) has 50 protons, Fluorine (F-) has 9 protons, Iron (Fe^{3+}) has 26 protons, Phosphorus (P^{3-}) has 15 protons, Vanadium (V) has 23 protons, Silver Ag(+) has 47 protons, Nitrogen (N^{3-}) has 7 protons.
02

Determine the number of electrons

In an ion, the number of electrons is the atomic number minus or plus the ion charge. For neutral atoms, the number of protons equals the number of electrons. Argon has 18 electrons, Tin Sn(4+) has 46 electrons, Fluorine (F-) has 10 electrons, Iron (Fe^{3+}) has 23 electrons, Phosphorus (P^{3-}) has 18 electrons, Vanadium has 23 electrons, Silver Ag(+) has 46 electrons, Nitrogen (N^{3-}) has 10 electrons.
03

Pair the species with the same number of electrons

Using the data obtained in step 2, pair the species that have the same number of electrons. The pairs are: Argon (Ar) and Phosphorus (P^{3-}), Tin Sn(4+) and Silver Ag(+), Fluorine (F-) and Nitrogen (N^{3-}), Iron (Fe^{3+}) and Vanadium (V).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free