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Chapter 2: Problem 48

What are the empirical formulas of the following compounds? (a) \(\mathrm{Al}_{2} \mathrm{Br}_{6}\) (b) \(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{4}\) (c) \(\mathrm{N}_{2} \mathrm{O}_{5}\) (d) \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\)

Short Answer

Expert verified
The empirical formulas for the compounds are: (a) \(\mathrm{AlBr}_{3}\), (b) \(\mathrm{NaSO}_{2}\), (c) \(\mathrm{N}_{2} \mathrm{O}_{5}\), (d) \(\mathrm{K}_{2}\mathrm{Cr}_{2}\mathrm{O}_{7}\)

Step by step solution

01

Understanding Empirical Formula

Empirical formula is a simple way of presenting a chemical compound. It shows the simplest ratio of atoms in a compound rather than the actual number.
02

Determining the Empirical Formula of Al2Br6

The given formula is \(\mathrm{Al}_{2} \mathrm{Br}_{6}\). This implies that the ratio of Al to Br atoms is 2:6. When simplified, this becomes 1:3, so the empirical formula is \(\mathrm{AlBr}_{3}\)
03

Determining the Empirical Formula of Na2S2O4

The given formula is \(\mathrm{Na}_{2} \mathrm{S}_{2} \mathrm{O}_{4}\). Here, the ratio of Na to S to O is 2:2:4. This simplifies to 1:1:2, so the empirical formula is \(\mathrm{NaSO}_{2}\)
04

Determining the Empirical Formula of N2O5

The given formula is \(\mathrm{N}_{2} \mathrm{O}_{5}\). The ratio of N to O atoms is 2:5, which is already in its simplest form. So the empirical formula is \(\mathrm{N}_{2} \mathrm{O}_{5}\)
05

Determining the Empirical Formula of K2Cr2O7

The given formula is \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\). The ratio of K to Cr to O is 2:2:7. This simplifies to 1:1:7/2, but rational number ratios are not used in empirical formulas. So, by multiplying each part of the ratio by 2, it becomes 2:2:7, so the empirical formula is \(\mathrm{K}_{2}\mathrm{Cr}_{2}\mathrm{O}_{7}\)

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Most popular questions from this chapter

For each of the following species, determine the number of protons and the number of neutrons in the nucleus: $${ }_{2}^{3} \mathrm{He},{ }_{2}^{4} \mathrm{He},{ }_{12}^{24} \mathrm{Mg},{ }_{12}^{25} \mathrm{Mg},{ }_{22}^{48} \mathrm{Ti},{ }_{35}^{79} \mathrm{Br},{ }_{78}^{195} \mathrm{Pt}$$

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