The following phosphorus sulfides are known: \(\mathrm{P}_{4} \mathrm{~S}_{3}\) \(\mathrm{P}_{4} \mathrm{~S}_{7},\) and \(\mathrm{P}_{4} \mathrm{~S}_{10} .\) Do these compounds obey the law of multiple proportions?

Short Answer

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Yes, the compounds \(\mathrm{P}_{4} \mathrm{~S}_{3}, \(\mathrm{P}_{4} \mathrm{~S}_{7},\) and \(\mathrm{P}_{4} \mathrm{~S}_{10}\) obey the law of multiple proportions as the ratios of the sulfur to phosphorus can be reduced to small whole numbers.

Step by step solution

01

Determine Mass Ratios

First, calculate the mass ratios of sulfur to phosphorus for each of the three compounds. To get these, divide the molar mass of sulfur in each compound by the molar mass of phosphorus in each compound. The molar mass of phosphorus is approximately \(30.97g/mol\) and the molar mass of sulfur is approximately \(32.06g/mol\).
02

Calculate Mass Ratios for Each Compound

For \(\mathrm{P}_{4} \mathrm{~S}_{3}\), the mass ratio is \((3*32.06)/(4*30.97)\). For \(\mathrm{P}_{4} \mathrm{~S}_{7}\), the mass ratio is \((7*32.06)/(4*30.97)\). For \(\mathrm{P}_{4} \mathrm{~S}_{10}\), the mass ratio is \((10*32.06)/(4*30.97)\).
03

Analyze the Ratios

Now determine if these ratios can be reduced to small whole numbers. If they can, these compounds obey the law of multiple proportions.
04

Final Conclusion

After performing the calculations, it is found that these compounds do obey the law of multiple proportions as the ratios can be reduced to small whole numbers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Laws

Understanding the fundamental laws that govern chemical reactions is crucial for making sense of how substances interact and change. One of these laws is called the law of multiple proportions, which states that when two elements combine to form more than one compound, the masses of one element that combine with a fixed mass of the other are in ratios of small whole numbers.

This law emphasizes the discrete and fixed nature of the chemical composition of compounds, reflecting the early understanding that matter is composed of atoms which can combine in simple, whole number ratios. It is an essential concept in chemistry because it underpins strategies for determining chemical formulas and understanding reaction mechanisms.

  • Illustrates the quantitative nature of chemical compounds
  • Helps predict the stoichiometry of reactions
  • Validates the atomic theory of matter
Stoichiometry

Stoichiometry is the branch of chemistry that deals with the quantitative relationships of elements and compounds as they undergo chemical reactions. It is the calculation of the amounts of reactants and products in chemical reactions and is based on the laws of conservation of mass and definite proportions.

For example, in a reaction where element A combines with element B to produce compound AB, stoichiometry allows us to calculate how much of A is needed to fully react with B, and vice versa. It provides a balanced equation to indicate the exact proportions of each substance involved in a reaction.

  • Central to predicting reaction yields and designing processes
  • Utilized for converting between masses, volumes, and particle counts in chemical equations
  • Involved in calculations of limiting reactants and percent yield
Molar Mass Calculations

Molar mass is a fundamental concept in stoichiometry, representing the mass of one mole of a substance, typically measured in grams per mole (g/mol). The molar mass of an element is numerically equal to its atomic weight from the periodic table and is essential for converting between mass and number of moles of a substance.

The calculation of molar mass involves adding up the atomic masses of all the atoms present in a molecule. For compounds, this means multiplying the atomic weight of each different type of atom by the number of atoms of that type in the molecule and summing the totals. As seen in the example of phosphorus sulfides, knowing the molar masses of both phosphorus and sulfur is key to determining the mass ratios and verifying the law of multiple proportions.

  • Necessary for stoichiometric calculations
  • Used to convert grams to moles, a fundamental step in many chemistry problems
  • Helps in determining empirical and molecular formulas of compounds
Phosphorus Sulfides

Phosphorus sulfides are binary compounds consisting of phosphorus and sulfur. They are interesting examples when discussing the law of multiple proportions because they can exist in various forms with different ratios of phosphorus to sulfur, such as \(\text{P}_4S_3, P_4S_7, \text{and} P_4S_{10}\).

By calculating the mass ratio of sulfur to phosphorus in these compounds, we can explore their adherence to chemical laws. Phosphorus sulfides also showcase the diversity of chemical compounds that can be formed from a simple combination of two nonmetal elements, demonstrating the complexity and variety that arises from atomic interactions.

  • Exhibit a variety of stoichiometries highlighting the law of multiple proportions
  • Demonstrate the diverse range of compounds that can result from different elemental ratios
  • Are useful for studying bond types and molecular structures in inorganic chemistry

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Most popular questions from this chapter

The Group \(1 \mathrm{~B}\) metals, \(\mathrm{Cu}, \mathrm{Ag},\) and \(\mathrm{Au},\) are called coinage metals. What chemical properties make them specially suitable for making coins and jewelry?

A cube made of platinum (Pt) has an edge length of \(1.0 \mathrm{~cm} .\) (a) Calculate the number of \(\mathrm{Pt}\) atoms in the cube. (b) Atoms are spherical in shape. Therefore, the \(\mathrm{Pt}\) atoms in the cube cannot fill all of the available space. If only 74 percent of the space inside the cube is taken up by Pt atoms, calculate the radius in picometers of a \(\mathrm{Pt}\) atom. The density of \(\mathrm{Pt}\) is \(21.45 \mathrm{~g} / \mathrm{cm}^{3}\) and the mass of a single \(\mathrm{Pt}\) atom is \(3.240 \times 10^{-22} \mathrm{~g}\). [The volume of a sphere of radius \(r\) is \(\left.(4 / 3) \pi r^{3} .\right]\)

In which one of the following pairs do the two species resemble each other most closely in chemical properties? Explain. (a) \({ }_{1}^{1} \mathrm{H}\) and \({ }_{1}^{1} \mathrm{H}^{+},\) (b) \({ }_{7}^{14} \mathrm{~N}\) and \({ }_{7}^{14} \mathrm{~N}^{3-},(\mathrm{c}){ }_{6}^{12} \mathrm{C}\) and \({ }_{6}^{13} \mathrm{C}\)

What are the empirical formulas of the following compounds? (a) \(\mathrm{Al}_{2} \mathrm{Br}_{6}\) (b) \(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{4}\) (c) \(\mathrm{N}_{2} \mathrm{O}_{5}\) (d) \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\)

Elements whose names end with "-ium" are usually metals; sodium is one example. Identify a nonmetal whose name also ends with "-ium".

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