What is wrong with the names (in parentheses) for each of the following compounds? \(\mathrm{SnCl}_{4}\) (tin chloride \(),\) (b) \(\mathrm{Cu}_{2} \mathrm{O}\) [ copper(II) oxide], (c) \(\mathrm{Co}\left(\mathrm{NO}_{3}\right)_{2}\) (cobalt nitrate), (d) \(\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) (sodium chromate)

Short Answer

Expert verified
The names of the compounds \(\mathrm{SnCl}_{4}\), \(\mathrm{Cu}_{2} \mathrm{O}\), \(\mathrm{Co}\left(\mathrm{NO}_{3}\right)_{2}\), and \(\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) should be Tin (IV) Chloride, Copper (I) Oxide, Cobalt (II) Nitrate and Sodium Dichromate respectively.

Step by step solution

01

Analyzing Tin (IV) Chloride

Thoroughly look at the compound and notice there are four chlorine atoms attached to the tin atom. Therefore, the correct name should be Tin (IV) Chloride because Tin is in the +4 oxidation state (the roman numeral represents the charge on Tin).
02

Analyzing Copper (I) Oxide

Take a glance at the compound and observe that copper is covalently bonded with only one oxygen atom. Hence, the right name for the compound is Copper (I) Oxide. The roman numeral (I) suggests that Copper has a +1 oxidation state.
03

Analyzing Cobalt (II) Nitrate

Looking at the compound shows two nitrate atoms bonded to the Cobalt atom. Therefore, Cobalt (II) Nitrate is indeed the correct name for the compound.
04

Analyzing Sodium Dichromate

We can see that there are two sodium atoms, two chromium atoms and seven oxygen atoms in the compound which suggests that the compound is Sodium Dichromate not Sodium Chromate. 'Di' prefix means two and chromate is CrO4. Therefore, the compound with two chromate ions is called dichromate.

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