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Chapter 21: Problem 22

State whether silicon would form \(n\) -type or \(p\) -type semiconductors with the following elements: Ga, \(\mathrm{Sb}, \mathrm{Al}, \mathrm{As}\)

Short Answer

Expert verified
Silicon would form \(p\)-type semiconductors when doped with Gallium (Ga) and Aluminum (Al), and \(n\)-type semiconductors when doped with Antimony (Sb) and Arsenic (As).

Step by step solution

01

Determine the number of valence electrons for Ga

Gallium (Ga) is in Group 13 of the periodic table which means it has 3 valence electrons.
02

Decide \(n\)-type or \(p\)-type for Ga

Since Ga has less than 4 valence electrons, when it is used to dope silicon, it will form a \(p\)-type semiconductor.
03

Determine the number of valence electrons for Sb

Antimony (Sb) is in Group 15 of the periodic table and therefore has 5 valence electrons.
04

Decide \(n\)-type or \(p\)-type for Sb

As Sb has more than 4 valence electrons, doping silicon with Sb will create an \(n\)-type semiconductor.
05

Determine the number of valence electrons for Al

Aluminum (Al) is in Group 13 of the periodic table and therefore has 3 valence electrons.
06

Decide \(n\)-type or \(p\)-type for Al

As Al has less than 4 valence electrons, doping silicon with Al will create a \(p\)-type semiconductor.
07

Determine the number of valence electrons for As

Arsenic (As) is in Group 15 of the periodic table and therefore has 5 valence electrons.
08

Decide \(n\)-type or \(p\)-type for As

As As has more than 4 valence electrons, doping silicon with As will create an \(n\)-type semiconductor.

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