Chapter 21: Problem 24
Why is potassium usually not prepared electrolytically from one of its salts?
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 21: Problem 24
Why is potassium usually not prepared electrolytically from one of its salts?
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeThe following are two reaction schemes involving magnesium. Scheme I: When magnesium burns in oxygen, a white solid (A) is formed. A dissolves in \(1 M \mathrm{HCl}\) to give a colorless solution (B). Upon addition of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) to \(\mathrm{B},\) a white precipitate is formed(C). On heating, C decomposes to \(D\) and a colorless gas is generated (E). When \(\mathrm{E}\) is passed through limewater [an aqueous suspension of \(\left.\mathrm{Ca}(\mathrm{OH})_{2}\right], \underline{\mathrm{a}}\) white precipitate appears (F). Scheme II:Magnesium reacts with \(1 M \mathrm{H}_{2} \mathrm{SO}_{4}\) to produce a colorless solution (G). Treating G with an excess of NaOH produces a white precipitate \((\mathrm{H}) . \mathrm{H}\) dissolves in \(1 M \mathrm{HNO}_{3}\) to form a colorless solution. When the solution is slowly evaporated, a white solid (I) appears. On heating I, a brown gas is given off. Identify \(\mathrm{A}-\mathrm{I}\) and write equations representing the reactions involved.
Write balanced equations for the following reactions: (a) the heating of aluminum carbonate; (b) the reaction between \(\mathrm{AlCl}_{3}\) and \(\mathrm{K} ;\) (c) the reaction between solutions of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) and \(\mathrm{Ca}(\mathrm{OH})_{2}\)
Which of the following compounds would require electrolysis to yield the free metals: \(\mathrm{Ag}_{2} \mathrm{~S}, \mathrm{CaCl}_{2}\) \(\mathrm{NaCl}, \mathrm{Fe}_{2} \mathrm{O}_{3}, \mathrm{Al}_{2} \mathrm{O}_{3}, \mathrm{TiCl}_{4} ?\)
What is wrong with the following procedure for obtaining magnesium?$$\begin{aligned}& \mathrm{MgCO}_{3} \longrightarrow \mathrm{MgO}(s)+\mathrm{CO}_{2}(g) \\\\\mathrm{MgO}(s)+\mathrm{CO}(g) & \longrightarrow \mathrm{Mg}(s)+\mathrm{CO}_{2}(g)\end{aligned}$$
A \(0.450-\mathrm{g}\) sample of steel contains manganese as an impurity. The sample is dissolved in acidic solution and the manganese is oxidized to the permanganate ion \(\mathrm{MnO}_{4}^{-}\). The \(\mathrm{MnO}_{4}^{-}\) ion is reduced to \(\mathrm{Mn}^{2+}\) by reacting with \(50.0 \mathrm{~mL}\) of \(0.0800 \mathrm{M} \mathrm{FeSO}_{4}\) solution. The excess \(\mathrm{Fe}^{2+}\) ions are then oxidized to \(\mathrm{Fe}^{3+}\) by \(22.4 \mathrm{~mL}\) of \(0.0100 \mathrm{M} \mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} .\) Calculate the percent by mass of manganese in the sample.
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