Starting with aluminum, describe with balanced equations how you would prepare (a) \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\) (b) \(\mathrm{Al}_{2} \mathrm{O}_{3}\) (c) \(\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}\) (d) \(\mathrm{NH}_{4} \mathrm{Al}\left(\mathrm{SO}_{4}\right)_{2} \cdot 12 \mathrm{H}_{2} \mathrm{O}\)

Short Answer

Expert verified
Preparation of (a) Al2Cl6 : 2 Al + 3 Cl2 -> 2 AlCl3, (b) Al2O3 : 4 Al + 3 O2 -> 2 Al2O3, (c) Al2(SO4)3 : 2 Al + 3 H2SO4 -> Al2(SO4)3 + 3 H2, (d) NH4Al(SO4)2.12H2O : Al2(SO4)3 + 2(NH4)2SO4 + 24 H2O -> 2 NH4Al(SO4)2.12H2O

Step by step solution

01

Preparation of Al2Cl6

Aluminum will react with Chlorine gas to form Aluminum Chloride (AlCl3). The balanced equation for this reaction is: \n2 Al (s) + 3 Cl2 (g) -> 2 AlCl3 (s)
02

Preparation of Al2O3

Aluminum will react with Oxygen to form Aluminum oxide (Al2O3). The balanced chemical reaction is: \n4 Al (s) + 3 O2 (g) -> 2 Al2O3 (s)
03

Preparation of Al2(SO4)3

Aluminum will react with Sulfuric acid to form Aluminium sulfate (Al2(SO4)3). The balanced equation for the reaction: \n2 Al (s) + 3 H2SO4 (aq) -> Al2(SO4)3 (aq) + 3 H2 (g)
04

Preparation of NH4Al(SO4)2.12H2O

Aluminium sulphate prepared in the previous step can further react with Ammonium sulfate to form Ammonium aluminium sulfate dodecahydrate. The balanced reaction is: \nAl2(SO4)3(aq) + 2(NH4)2SO4(aq) + 24 H2O(l) -> 2 NH4Al(SO4)2.12H2O(s)

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