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Chapter 23: Problem 23

The complex ion \(\left[\mathrm{Ni}(\mathrm{CN})_{2} \mathrm{Br}_{2}\right]^{2-}\) has a squareplanar geometry. Draw the structures of the geometric isomers of this complex.

Short Answer

Expert verified
The complex ion \([\mathrm{Ni}(\mathrm{CN})_{2}\mathrm{Br}_{2}\]^{2-}\) has two geometric isomers: the cis isomer, with CN ligands adjacent to each other and Br ligands adjacent to each other, and the trans isomer, with CN ligands opposite to each other and Br ligands opposite to each other.

Step by step solution

01

Understand the structure of the complex

The given complex ion \([\mathrm{Ni}(\mathrm{CN})_{2}\mathrm{Br}_{2}\]^{2-}\) is square planar. This means that the central atom, Nickel in this case, is at the center of a square and is bonded to four other ligands (two CN and two Br), which are positioned at the corners of the square.
02

Identify the ligands

The ligands in our complex ion are two cyanides (CN) and two bromides (Br). These will move around the Nickel atom to form different geometric isomers.
03

Draw the geometric isomers

There are two geometric isomers for this complex ion. One isomer is the 'cis' isomer, where the same types of ligands are adjacent to each other. It will have CN ligands on adjacent corners and Br ligands on the other two corners. The other isomer is the 'trans' isomer, where the same types of ligands are opposite to each other. It will have CN ligands on opposite corners and Br ligands on the remaining corners. It's important to correctly draw these representations to distinguish between the two.

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