The enthalpy change in the denaturation of a certain protein is \(125 \mathrm{~kJ} / \mathrm{mol} .\) If the entropy change is \(397 \mathrm{~J} / \mathrm{K} \cdot \mathrm{mol},\) calculate the minimum temperature at which the protein would denature spontaneously.

Short Answer

Expert verified
The minimum temperature at which the protein would denature spontaneously is greater than 315.11 Kelvin.

Step by step solution

01

Interpret the given information

The problem provides the change in the enthalpy \(\Delta H = 125 \, \mathrm{kJ/mol}\) and the change in entropy \(\Delta S = 397 \, \mathrm{J/(K \cdot mol)}\) during the denaturation of a protein.
02

Convert the units

Before calculating, make sure that \(\Delta H\) and \(\Delta S\) are in compatible units. Here, \(\Delta H\) is given in \(\mathrm{kJ/mol}\), and \(\Delta S\) is given in \(\mathrm{J/(K \cdot mol)}\). Convert \(\Delta H\) from \(\mathrm{kJ/mol}\) to \(\mathrm{J/mol}\) by multiplying by 1000. \[ \Delta H = 125000 \, \mathrm{J/mol} \]
03

Set up the Gibbs free energy equation

According to the Gibbs free energy equation \( \Delta G = \Delta H - T\Delta S \). This equation has to be negative (\( \Delta G < 0 \)) for spontaneity. \[ \Delta H - T\Delta S < 0 \] Solve for the temperature (\(T\)). \[ T > \frac{\Delta H} {\Delta S} \]
04

Substitute the given values

Now, substitute the given values for \(\Delta H\) and \(\Delta S\) into the equation. \[ T > \frac{125000 \, \mathrm{J/mol}}{397 \, \mathrm{J/(K \cdot mol)}} \]
05

Calculate the minimum temperature

After completing the division, round the result to two decimal places to get: \( T > 315.11 \, K \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gibbs Free Energy
Gibbs free energy, represented by the symbol \( \Delta G \), is the amount of reversible work obtainable from a system at constant temperature and pressure. It's a measure of the maximum usable energy from a thermodynamic process and is crucial in predicting the direction of a chemical reaction. A negative \( \Delta G \) value implies that a reaction is spontaneous, while a positive \( \Delta G \) means it is non-spontaneous and requires energy.

For protein denaturation, the Gibbs free energy equation \( \Delta G = \Delta H - T\Delta S \) integrates enthalpy (\( \Delta H \), the heat absorbed or released) and entropy (\( \Delta S \), the disorder of a system), accounting for the temperature (\( T \)) influence. Spontaneous denaturation will occur when \( \Delta G \) is less than zero, indicating that the process is energetically favorable without external energy input.
Spontaneity of Reactions
The spontaneity of a chemical reaction is a term used to describe whether a reaction can occur under a set of given conditions without the need for continuous external intervention. It is not an indicator of the speed of the reaction but rather its inherent tendency to proceed. In the context of protein denaturation, analyzing spontaneity requires understanding the changes in both enthalpy (heat exchange) and entropy (disorder) during the process.

From a thermodynamic perspective, spontaneity is driven by Gibbs free energy, and the condition for a spontaneous reaction is \( \Delta G < 0 \). In our protein denaturation exercise, we derive the temperature at which spontaneity is achieved by rearranging the Gibbs free energy equation to \( T > \frac{\Delta H}{\Delta S} \). Once \( T \) exceeds this threshold, the entropy factor (\( T\Delta S \) term) outweighs the enthalpy change, leading to a negative \( \Delta G \) and spontaneous denaturation.
Units Conversion in Chemistry
In chemistry, it's essential to perform units conversion meticulously to ensure that calculations are accurate. Different units of measurement can be used to express energy, temperature, pressure, and concentration, and converting them correctly is crucial in calculations like those involving Gibbs free energy.

In the case of our protein denaturation problem, the enthalpy change \( \Delta H \) was provided in kilojoules per mole (\( \mathrm{kJ/mol} \)) while the entropy change \( \Delta S \) was given in joules per kelvin per mole (\( \mathrm{J/(K \cdot mol)} \)). For the Gibbs free energy equation to work, both must be in the same energy unit. Thus, converting \( \Delta H \) from \( \mathrm{kJ/mol} \) to \( \mathrm{J/mol} \) by multiplying by 1000 is essential. This conversion allows us to determine the minimum temperature for spontaneous protein denaturation by inserting compatible units into the equation, showing how crucial attention to units is in guiding the correctness of chemical calculations.

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Most popular questions from this chapter

The average distance between base pairs measured parallel to the axis of a DNA molecule is 3.4 Å (see Figure 25.19 ). The average molar mass of a pair of nucleotides is \(650 \mathrm{~g} / \mathrm{mol} .\) Estimate the length in centimeters of a DNA molecule of molar mass \(5.0 \times\) \(10^{9} \mathrm{~g} / \mathrm{mol}\)

The "melting point" of a DNA molecule is the temperature at which the double- helical strand breaks apart. Suppose you are given two DNA samples. One sample contains 45 percent C-G base pairs while the other contains 64 percent C-G base pairs. The total number of bases is the same in each sample. Which of the two samples has a higher melting point? Why?

Molar mass measurements play an important role in characterizing polymer solutions. Number-average molar mass \(\left(\bar{M}_{n}\right)\) is defined as the total molar mass (given by \(\Sigma N_{i} M_{i}\) ) divided by the total number of molecules: $$ \bar{M}_{n}=\frac{\Sigma N_{i} M_{i}}{\Sigma N_{i}} $$ where \(N_{i}\) is the number of molecules with molar mass \(M_{i}\). Another important definition is the weightaverage molar mass \(\left(\bar{M}_{w}\right)\) where $$\bar{M}_{w}=\frac{\Sigma N_{i} M_{i}^{2}}{\Sigma N_{i} M_{i}}$$ The difference between these two definitions is that \(\bar{M}_{w}\) is based on experimental measurements that are affected by the size of molecules. (a) Consider a solution containing five molecules of molar masses \(1.0,3.0,4.0,4.0,\) and \(6.0 \mathrm{~kg} / \mathrm{mol} .\) Calculate both \(\bar{M}_{n}\) and \(\bar{M}_{w}\). (b) \(\bar{M}_{w}\) is always greater than \(\bar{M}_{n}\) because of the square term in the definition. However, if all the molecules have identical molar mass, then we have \(\bar{M}_{n}=\bar{M}_{w} .\) Show that this is the case if we have four molecules having the same molar mass of \(5 \mathrm{~kg} / \mathrm{mol} .\) (c) Explain how a comparison of these two average molar masses gives us information about the distribution of the size of synthetic polymers like polyethylene and poly(vinyl chloride). (d) Proteins like myoglobin and cytochrome \(c\) have the same \(\bar{M}_{n}\) and \(\bar{M}_{w},\) while this is not the case for hemoglobin. Explain.

The "melting point" of a DNA molecule is the temperature at which the double- helical strand breaks apart. Suppose you are given two DNA samples. One sample contains 45 percent C-G base pairs while the other contains 64 percent C-G base pairs. The total number of bases is the same in each sample. Which of the two samples has a higher melting point? Why?

Vinyl chloride, \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CHCl}\), undergoes copolymerization with 1,1 -dichloroethylene, \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CCl}_{2},\) to form a polymer commercially known as Saran. Draw the structure of the polymer, showing the repeating monomer units.

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