How many moles of calcium (Ca) atoms are in \(77.4 \mathrm{~g}\) of \(\mathrm{Ca} ?\)

Short Answer

Expert verified
The number of moles of Calcium (Ca) atoms in \(77.4 \, g\) of Ca is approximately \(1.93 \, mol\).

Step by step solution

01

Identifying the Knowns

We know that the molar mass of Calcium (Ca) is \(40.08 \, \frac{g}{mol}\), and here we are given that the mass of Ca is \(77.4 \, g\).
02

Applying the Formula

The formula to calculate the number of moles \(n\) from the mass \(m\) and the molar mass \(M\) is \( n = \frac{m}{M} \).
03

Substituting the Knowns into the Formula

Substituting our known values into the equation gives us \( n = \frac{77.4 \, g}{40.08 \, \frac{g}{mol}} \).
04

Calculating the Result

Calculating the expression results in \( n \approx 1.93 \, mol \). The number of moles is a dimensionless quantity, so it does not have a unit of measure.

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