What is the mass in grams of \(1.00 \times 10^{12}\) lead \((\mathrm{Pb})\) atoms?

Short Answer

Expert verified
To find the exact result, one would need a calculator. However, the final result should be in grams reflecting the mass of \(1.00 \times 10^{12}\) lead atoms.

Step by step solution

01

Conversion of number of atoms to moles

The number of moles of lead can be calculated by dividing the given number of atoms by Avogadro's number. So, the number of moles \(n\) of Pb is: \(n = \frac{1.00 \times 10^{12}}{6.022 \times 10^{23}}\).
02

Conversion of moles to grams

The mass of lead can be found by multiplying the number of moles by the molar mass of lead. The molar mass of lead is 207.2 g/mol. So, the mass \(m\) in grams is: \(m = n \times 207.2\).
03

Calculate and Simplify

Now carrying out the multiplication operation, a calculator might be required due to the extensive numbers.

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