Calculate the molecular mass or formula mass (in amu) of each of the following substances: (a) \(\mathrm{CH}_{4}\) (b) \(\mathrm{NO}_{2},(\mathrm{c}) \mathrm{SO}_{3},(\mathrm{~d}) \mathrm{C}_{6} \mathrm{H}_{6}\) (e) NaI, (f) \(\mathrm{K}_{2} \mathrm{SO}_{4}\) \((\mathrm{g}) \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}\)

Short Answer

Expert verified
The molecular or formula masses are: (a) 16.042 amu, (b) 46.01 amu, (c) 80.07 amu, (d) 78.114 amu, (e) 149.89 amu, (f) 174.27 amu, (g) 310.18 amu.

Step by step solution

01

Determine atomic masses

First, one must determine the atomic masses of the elements in each molecule or ionic compound. This information can be found on a periodic table. The atomic masses are (all values in atomic mass units or amu) \nCarbon: 12.01, Hydrogen: 1.008, Nitrogen: 14.01, Oxygen: 16.00, Sulfur: 32.07, Sodium: 22.99, Iodine: 126.90, Potassium: 39.10, Calcium: 40.08, Phosphorus: 30.97.
02

Calculate the molecular mass

Then, calculate the molecular mass in each compound by adding up the atomic masses of its elements.\n For CH4, there are 1 carbon atom and 4 hydrogen atoms, so (1*12.01) + (4*1.008) =16.042 amu\nFor NO2, there are 1 nitrogen atom and 2 oxygen atoms, so (1*14.01) + (2*16.00) = 46.01 amu\n For C6H6, there are 6 carbon atoms and 6 hydrogen atoms, so (6*12.01) + (6*1.008) = 78.114 amu
03

Calculate the formula mass

For ionic compounds, such as NaI and K2SO4, calculate the formula mass by adding up the atomic masses of its elements.\n For NaI, there is 1 sodium atom and 1 iodine atoms, so (1*22.99) + (1*126.90) = 149.89 amu\n For K2SO4, there are 2 potassium atoms, 1 sulfur atom and 4 oxygen atoms, so (2*39.10) + (1*32.07) + (4*16.00) = 174.27 amu\n For Ca3(PO4)2, there are 3 calcium atoms, 2 phosphorus atoms and 8 oxygen atoms, so (3*40.08) + (2*30.97) + (8*16.00) = 310.18 amu
04

Conclusion

After calculating the molecular or formula mass for each of the given substances, you have now completed the exercise. Remember that these are the masses of one single molecule or formula unit of the substance, not the mass of a sample or a mole of the substance in real life. The calculations and determinations made in this process are vital in Chemistry for understanding stoichiometry, balancing chemical reactions, and other important concepts.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemistry Education
Chemistry education is the guiding force behind empowering students with the knowledge to decode the intricate language of chemicals and their interactions. It's a discipline that goes beyond mere memorization of elements and reactions; it involves critical thinking and an understanding of fundamental concepts that explain the behavior of matter. One such foundational concept is the calculation of molecular masses, an essential skill for students beginning their exploration into chemistry.Through these exercises, students learn not only how atoms combine to form molecules but also the quantitative aspect of these combinations. Undertaking problems involving molecular mass calculations reinforces their familiarity with the periodic table and hones their mathematical skills within a chemistry context, ultimately building a solid base for more advanced topics in stoichiometry and chemical reactions.
Stoichiometry
Stoichiometry is at the heart of chemical mathematics. It's the section of chemistry that deals with the quantitative relationships between the substances involved in chemical reactions. Understanding stoichiometry begins with the ability to calculate the molecular mass of compounds. This calculation allows chemists to predict how much of each substance will react or be produced in a given chemical reaction.

When students grasp stoichiometry, they unlock the ability to quantify reactants and products, design experiments, and even scale up reactions for industrial applications. By learning to calculate molecular masses, students are taking their first steps towards mastering this crucial concept, preparing them for the challenges of balancing equations and converting between grams, moles, and particles.
Atomic Mass
The atomic mass, often referred to as atomic weight, is a weighted average that reflects the varied natural isotopic distribution of an element. Expressed in atomic mass units (amu), each element's atomic mass is a fundamental attribute documented on the periodic table. In calculating molecular masses, students must accurately reference these values to determine the mass of a compound.

Understanding atomic mass is crucial not only for stoichiometry but also for other areas of chemistry like isotope geochemistry and spectroscopy. It's a bridge between the microscopic world of atoms and the macroscopic realm of grams and liters that we experience in everyday life. Exercises that require determining atomic masses are more than routine calculations; they are practice in precision and attention to detail, traits indispensable for any aspiring chemist.
Periodic Table
The periodic table is the chemist's roadmap, charting the landscape of elements that compose our world. Its tabular arrangement is not arbitrary; it reflects patterns in the properties of the elements, including atomic mass. By referencing the periodic table, students can find the atomic masses needed for molecular mass calculations. With its columns and rows, the periodic table also hints at the underlying structure of atoms and their chemical behavior.

As students navigate molecular mass problems, they must become adept at using the periodic table not just as a source of data but as a conceptual framework for understanding chemical properties. This tool is indispensable when it comes to predicting reactivity, understanding trends, and explaining the rationale behind the formation of complex compounds.

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Most popular questions from this chapter

A research chemist used a mass spectrometer to study the two isotopes of an element. Over time, she recorded a number of mass spectra of these isotopes. On analysis, she noticed that the ratio of the taller peak (the more abundant isotope) to the shorter peak (the less abundant isotope) gradually increased with time. Assuming that the mass spectrometer was functioning normally, what do you think was causing this change?

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