Chapter 3: Problem 25
Calculate the molar mass of a compound if 0.372 mole of it has a mass of \(152 \mathrm{~g}\).
Short Answer
Expert verified
The molar mass of the compound is approximately 408.6 g/mol.
Step by step solution
01
Identify given values
In the problem, the given values are the mass of the substance \( m = 152 \, g \) and the number of moles \( n = 0.372 \, moles \) . The quantity that needs to be found is the molar mass (M).
02
Use the formula to find molar mass
Now, use the formula for the molar mass \( M = \frac{m}{n} \) where m is the given mass and n is the given moles. It yields \( M = \frac{152 \, g}{0.372 \, moles} \)
03
Solve the equation
Now that we have all the values, we solve the equation \( M = \frac{152 \, g}{0.372 \, moles} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Stoichiometry
Stoichiometry is a branch of chemistry that deals with the quantitative relationships between the reactants and products in a chemical reaction. It is based on the law of conservation of mass, which states that matter is neither created nor destroyed in a chemical reaction. Therefore, the amount of each substance involved can be related using a balanced chemical equation.
In practical terms, stoichiometry allows us to predict the amounts of products formed from given reactants or the amounts of reactants needed to produce desired products. This is crucial for tasks such as scaling up reactions for industrial production or simply synthesize a particular compound in a lab.
When calculating molar masses within the context of stoichiometry, it is important to understand that the molar mass acts as a conversion factor between moles, the unit of amount in chemistry, and grams, a more standard unit of mass. This conversion is essential because chemical equations are typically expressed in terms of moles.
In practical terms, stoichiometry allows us to predict the amounts of products formed from given reactants or the amounts of reactants needed to produce desired products. This is crucial for tasks such as scaling up reactions for industrial production or simply synthesize a particular compound in a lab.
When calculating molar masses within the context of stoichiometry, it is important to understand that the molar mass acts as a conversion factor between moles, the unit of amount in chemistry, and grams, a more standard unit of mass. This conversion is essential because chemical equations are typically expressed in terms of moles.
Mole Concept
The mole concept is a fundamental concept in chemistry that defines the amount of substance. One mole is defined as the amount of substance that contains the same number of entities (atoms, molecules, ions, or other particles) as there are atoms in 12 grams of pure carbon-12.
The number of entities in a mole is known by Avogadro's number, which is approximately \(6.022 \times 10^{23}\). This extensive number is used because atoms and molecules are exceedingly small and in any typical amount of a substance results in a large number of them.
In a molar mass calculation, we use the mole concept to relate the mass of a substance to the number of particles it contains. This allows us to derive how much one mole of a substance weighs; the definition of molar mass. For instance, if 0.372 mole of a substance weighs 152 grams, then the molar mass of that substance is the mass divided by the number of moles, resulting in the weight of one mole of that substance.
The number of entities in a mole is known by Avogadro's number, which is approximately \(6.022 \times 10^{23}\). This extensive number is used because atoms and molecules are exceedingly small and in any typical amount of a substance results in a large number of them.
In a molar mass calculation, we use the mole concept to relate the mass of a substance to the number of particles it contains. This allows us to derive how much one mole of a substance weighs; the definition of molar mass. For instance, if 0.372 mole of a substance weighs 152 grams, then the molar mass of that substance is the mass divided by the number of moles, resulting in the weight of one mole of that substance.
Chemical Calculations
Chemical calculations are used to determine various quantities in chemistry such as the amount of reactants, the concentration of solutions, or the yield of a reaction. One of the most fundamental chemical calculations is finding the molar mass of a substance, as seen in the example exercise.
The steps involved in such a calculation are straight forward. Having identified the mass and the number of moles of a substance, one can use the formula \(M = \frac{m}{n}\) to find its molar mass. This process neatly illustrates the connection between the theoretical concepts of stoichiometry and the mole concept with practical laboratory applications.
With this knowledge, not only are students able to tackle textbook exercises but also gather the comprehension to predict and calculate necessary reagents and products for actual chemical reactions they may encounter in their educational or professional laboratory experiences.
The steps involved in such a calculation are straight forward. Having identified the mass and the number of moles of a substance, one can use the formula \(M = \frac{m}{n}\) to find its molar mass. This process neatly illustrates the connection between the theoretical concepts of stoichiometry and the mole concept with practical laboratory applications.
With this knowledge, not only are students able to tackle textbook exercises but also gather the comprehension to predict and calculate necessary reagents and products for actual chemical reactions they may encounter in their educational or professional laboratory experiences.