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Chapter 3: Problem 37

Tin (Sn) exists in Earth's crust as \(\mathrm{SnO}_{2}\). Calculate the percent composition by mass of \(\mathrm{Sn}\) and \(\mathrm{O}\) in \(\mathrm{SnO}_{2}\)

Short Answer

Expert verified
The percent composition by mass of Tin (Sn) in \(\mathrm{SnO}_{2}\) is 78.77% and for Oxygen (O) is 21.23%.

Step by step solution

01

Calculate the Molar Masses

First, you need to determine the molar mass of each of the elements and the compound. Using the atomic weights from the periodic table, the atomic weight of Tin (Sn) is approximately 118.71 g/mol and for Oxygen (O) is approximately 16.00 g/mol. For \(\mathrm{SnO}_{2}\), multiply the atomic weight of Oxygen by 2 and then add the atomic weight of Tin: \(118.71 + 2(16.00) = 150.71 g/mol\).
02

Calculate the Percent Composition

Then, calculate the percent composition of Tin (Sn) and Oxygen (O) in \(\mathrm{SnO}_{2}\). The formula is \((\text{mass of element} / \text{molar mass of compound}) \times 100\% \). For Tin (Sn), it's \( (118.71 g/mol / 150.71 g/mol) \times 100\%= 78.77\%\). For Oxygen (O), it's \((2(16.00 g/mol) / 150.71 g/mol) \times 100\% = 21.23\%\).

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Most popular questions from this chapter

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