The formula for rust can be represented by \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) How many moles of Fe are present in \(24.6 \mathrm{~g}\) of the compound?

Short Answer

Expert verified
0.308 moles of Fe are present in 24.6 g of the compound.

Step by step solution

01

Molar Mass of Fe2O3

The molar mass of Fe2O3 can be calculated with the atomic masses of iron (Fe) and oxygen (O). Using the atomic masses from the periodic table (Fe = 55.85 g/mol, O = 16 g/mol), the molar mass of Fe2O3 = 2(55.85 g/mol) + 3(16 g/mol) = 159.7 g/mol.
02

Find moles of Fe2O3

Now, the number of moles of Fe2O3 can be calculated from the given mass. According to Molar mass concept, Moles = mass/ molar mass, so, Moles of Fe2O3 = 24.6 g / 159.7 g/mol = 0.154 moles.
03

Use Mole Ratio to Find Moles of Fe

The chemical formula of rust indicates that for each mole of Fe2O3, there are 2 moles of Fe. This 2:1 ratio must be used to find the moles of Fe. Multiply the moles of Fe2O3 by 2, Moles of Fe = 0.154 moles * 2 = 0.308 moles.

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