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Chapter 4: Problem 151

Is the following reaction a redox reaction? Explain. \(3 \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{O}_{3}(g)\)

Short Answer

Expert verified
No, the given reaction is not a redox reaction because there is no change in the oxidation states of the elements involved. No loss or gain of electrons has occurred.

Step by step solution

01

Understand the reaction

Firstly, identify the reactant and product of the reaction given. Here, the reaction shows \(3 \mathrm{O}_{2}(g)\) as the reactant converting into \(2 \mathrm{O}_{3}(g)\) as the product.
02

Determine oxidation states

Oxygen in its elemental state \(\mathrm{O}_{2}(g)\) has an oxidation state of 0. In the ozone molecule \(\mathrm{O}_{3}(g)\), oxygen is also in its elemental state and thus maintains the oxidation state of 0.
03

Identify changes in oxidation states

The oxidation states of oxygen in both reactant and product is 0, which means there is no change in oxidation state. This indicates that no electrons were transferred.
04

Conclude from findings

Since there are no changes in the oxidation states of any atoms in the reaction, it can be concluded that this is not a redox reaction as no reduction or oxidation occurred.

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Most popular questions from this chapter

Write the equation that enables us to calculate the concentration of a diluted solution. Give units for all the terms.

The \(\mathrm{SO}_{2}\) present in air is mainly responsible for the acid rain phenomenon. Its concentration can be determined by titrating against a standard permanganate solution as follows: \(5 \mathrm{SO}_{2}+2 \mathrm{MnO}_{4}^{-}+2 \mathrm{H}_{2} \mathrm{O} \longrightarrow\) \(5 \mathrm{SO}_{4}^{2-}+2 \mathrm{Mn}^{2+}+4 \mathrm{H}^{+}\) Calculate the number of grams of \(\mathrm{SO}_{2}\) in a sample of air if \(7.37 \mathrm{~mL}\) of \(0.00800 \mathrm{M} \mathrm{KMnO}_{4}\) solution are required for the titration.

Write the equation for calculating molarity. Why is molarity a convenient concentration unit in chemistry?

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