Chapter 4: Problem 45
Arrange the following species in order of increasing oxidation number of the sulfur atom: (a) \(\mathrm{H}_{2} \mathrm{~S},\) (b) \(\mathrm{S}_{8}\), (c) \(\mathrm{H}_{2} \mathrm{SO}_{4},\) (d) \(\mathrm{S}^{2-}\) (e) \(\mathrm{HS}^{-}\) (f) \(\mathrm{SO}_{2},(\mathrm{~g}) \mathrm{SO}_{3}\)
Short Answer
Expert verified
The species are arranged in increasing oxidation number of sulfur as follows: S2- = H2S = HS- -> S8 -> SO2 -> H2SO4 = SO3.
Step by step solution
01
Assigning oxidation numbers to H2S
In H2S, hydrogen is +1 in all of its compounds. Thus, the oxidation number of S in H2S is -2 because the sum of the oxidation numbers in a neutral compound must be 0, and we have 2 hydrogen atoms each with an oxidation number of +1, thus the sulfur atom must be -2 to get a sum of 0.
02
Assigning oxidation numbers to S8
In S8, sulfur is in its elemental state. The oxidation number of an atom in its elemental state is always 0.
03
Assigning oxidation numbers to H2SO4
In H2SO4, hydrogen is +1 and oxygen is -2. To find the oxidation number of sulfur, we set up an equation: 2(1) + x + 4(-2) = 0; this solves to x = 6, so the oxidation number of sulfur in H2SO4 is +6.
04
Assigning oxidation numbers to S2-
S2- represents sulfur ion with a charge of -2. The oxidation number of any monoatomic ion is equal to its charge. Thus, the oxidation number of sulfur in S2- is -2.
05
Assigning oxidation numbers to HS-
In HS-, sulfur is bonded to hydrogen which is +1. As the overall charge of HS- is -1, the oxidation number of sulfur has to be -2.
06
Assigning oxidation numbers to SO2
In SO2, oxygen is -2. To find the oxidation number of sulfur, we set up an equation: x + 2(-2) = 0; this solves to x = 4, so the oxidation number of sulfur in SO2 is +4.
07
Assigning oxidation numbers to SO3
In SO3, similar as in SO2, oxygen is -2. But this time we have 3 oxygen atoms, so to find the oxidation number of sulfur, we set up an equation: x + 3(-2) = 0; this solves to x = 6, so the oxidation number of sulfur in SO3 is +6.
08
Arrange species in the increasing oxidation number
So, arranging the species from lowest to highest oxidation number of sulfur, we get: S2- = H2S = HS- -> S8 -> SO2 -> H2SO4 = SO3.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Assigning Oxidation States
Understanding oxidation states is essential in mastering redox chemistry, as they tell us about how electrons are distributed in compounds and which atoms are undergoing changes in redox reactions. Assigning oxidation states involves several rules:
- The oxidation state of pure elements is always zero.
- For monoatomic ions, the oxidation state is equal to the ionic charge.
- In most compounds, hydrogen has an oxidation state of +1, while oxygen has an oxidation state of -2.
- The sum of oxidation states in a neutral compound must be zero, and in ions, it must equal the charge of the ion.
Redox Chemistry
Redox chemistry is the branch of chemistry that studies oxidation-reduction reactions, where the oxidation states of atoms are changed. Oxidation involves the loss of electrons, leading to an increase in oxidation state, while reduction involves the gain of electrons, with a corresponding decrease in oxidation state.
Understanding redox reactions requires not only knowing how to assign oxidation states but also recognizing the signs of oxidation and reduction processes. In the given exercise, identifying the oxidation states allows us to infer the reduction or oxidation tendencies of sulfur across different species. For example, when sulfur goes from an oxidation state of -2 in to +6 in sulfuric acid (), it indicates that it has lost electrons, undergoing an oxidation process. Redox reactions are common in many chemical processes, including metabolism in living organisms, industrial synthesis of chemicals, and even the rusting of iron.
Understanding redox reactions requires not only knowing how to assign oxidation states but also recognizing the signs of oxidation and reduction processes. In the given exercise, identifying the oxidation states allows us to infer the reduction or oxidation tendencies of sulfur across different species. For example, when sulfur goes from an oxidation state of -2 in to +6 in sulfuric acid (), it indicates that it has lost electrons, undergoing an oxidation process. Redox reactions are common in many chemical processes, including metabolism in living organisms, industrial synthesis of chemicals, and even the rusting of iron.
Sulfur Oxidation States
Sulfur is a versatile element that exhibits a wide range of oxidation states, from -2 in sulfide ions to +6 in sulfate ions. This flexibility is seen in the exercise where sulfur's oxidation state varies across several compounds.
- and : Sulfur has the lowest oxidation state of -2, compatible with the sulfur ion and hydrogen sulfide.
- : As an elemental form of sulfur, the oxidation state is 0.
- and : These represent oxidation states of +4 and +6 for sulfur respectively, corresponding to sulfur dioxide and sulfur trioxide.
Balancing Redox Equations
Balancing redox equations is a key skill in understanding chemical reactions. This process ensures that the mass and charge are conserved during a reaction. To balance redox equations, one generally follows these steps:
- Determine the oxidation states of atoms to identify the oxidized and reduced species.
- Write half-reactions for the oxidation and reduction processes, balancing all atoms except oxygen and hydrogen.
- Balance oxygen atoms by adding water molecules and hydrogen atoms by adding hydrogen ions.
- Balance the charges by adding electrons.
- Combine the half-reactions, ensuring that the number of electrons lost in oxidation equals the number of electrons gained in reduction.
- Add any further necessary species to balance the atoms in the combined equation.