On the basis of oxidation number considerations, one of the following oxides would not react with molecular oxygen: \(\mathrm{NO}, \mathrm{N}_{2} \mathrm{O}, \mathrm{SO}_{2}, \mathrm{SO}_{3}, \mathrm{P}_{4} \mathrm{O}_{6}\) Which one is it? Why?

Short Answer

Expert verified
The oxide that would not react with molecular oxygen is \(\mathrm{SO}_{3}\) because sulfur in this compound is already in its highest oxidation state (+6), thus it cannot be further oxidized.

Step by step solution

01

Recall the Oxidation Numbers

An oxidation number is a measure of the degree of oxidation of an atom in a substance. For example, the oxidations states for nitrogen can range from -3 to +5, sulfur from -2 to +6 and phosphorus from -3 to +5.
02

Apply the Oxidation Numbers

Let's take a look at the given substances: \(\mathrm{NO}\) has nitrogen at +2, \(\mathrm{N}_{2} \mathrm{O}\) has nitrogen at +1, \(\mathrm{SO}_{2}\) has sulfur at +4, \(\mathrm{SO}_{3}\) has sulfur at +6 and \(\mathrm{P}_{4}\mathrm{O}_{6}\) has phosphorus at +3.
03

Determine the Highest Oxidation State

Among the substances given, sulfur in \(\mathrm{SO}_{3}\) is already at its highest oxidation state of +6. This means that it cannot be further oxidized by molecular oxygen.

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Most popular questions from this chapter

Chemical tests of four metals \(\mathrm{A}, \mathrm{B}, \mathrm{C},\) and \(\mathrm{D}\) show the following results. (a) Only \(\mathrm{B}\) and \(\mathrm{C}\) react with \(0.5 \mathrm{M} \mathrm{HCl}\) to give \(\mathrm{H}_{2}\) gas. (b) When \(\mathrm{B}\) is added to a solution containing the ions of the other metals, metallic \(\mathrm{A}, \mathrm{C},\) and \(\mathrm{D}\) are formed. (c) A reacts with \(6 M \mathrm{HNO}_{3}\) but \(\mathrm{D}\) does not. Arrange the metals in the increasing order as reducing agents. Suggest four metals that fit these descriptions.

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