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Chapter 4: Problem 59

Write the equation for calculating molarity. Why is molarity a convenient concentration unit in chemistry?

Short Answer

Expert verified
The equation for molarity (M) is: \(M = \frac{\text{{moles of solute}}} {\text{{liters of solution}}}\). Molarity is a useful concentration unit in chemistry because it provides an easy, quantitative method for comparing the concentrations of different solutions. It is crucial for understanding and predicting reaction outcomes.

Step by step solution

01

Write out the formula for calculating molarity

Molarity is defined as the number of moles of solute per liter of solution. The equation for molarity (M) is formulated as: \(M = \frac{\text{{moles of solute}}} {\text{{liters of solution}}}\).
02

Explain the convenience of the molarity unit

Molarity is a convenient concentration unit in chemistry for multiple reasons. First, it is easy to calculate. Second, it directly communicates the number of moles present in a liter of solution, enabling quantitative understanding and analysis of reactions. Lastly, it facilitates easy comparison and standardization of concentrations across different solutions. Thus, molarity effectively quantifies the concentration which is essential for understanding and predicting reaction outcomes. It is particularly useful when dealing with solutions in chemical reactions as it enables chemists to determine the precise amounts of reactants required, ensuring accurate stoichiometric calculations.

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Most popular questions from this chapter

Carbon dioxide in air can be removed by an aqueous metal hydroxide solution such as \(\mathrm{LiOH}\) and \(\mathrm{Ba}(\mathrm{OH})_{2} .\) (a) Write equations for the reactions. (Carbon dioxide reacts with water to form carbonic acid.) (b) Calculate the mass of \(\mathrm{CO}_{2}\) that can be removed by \(5.00 \times 10^{2} \mathrm{~mL}\) of a \(0.800 \mathrm{M} \mathrm{LiOH}\) and a \(0.800 M \mathrm{Ba}(\mathrm{OH})_{2}\) solution. (c) Which solution would you choose for use in a space capsule and which for use in a submarine?

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