Chapter 6: Problem 49
In general, compounds with negative \(\Delta H_{i}^{\circ}\) values are more stable than those with positive \(\Delta H_{i}^{\circ}\) values. \(\mathrm{H}_{2} \mathrm{O}_{2}(l)\) has a negative \(\Delta H_{\mathrm{f}}^{\circ}\) (see Table 6.4 ). Why, then, does \(\mathrm{H}_{2} \mathrm{O}_{2}(l)\) have a tendency to decompose to \(\mathrm{H}_{2} \mathrm{O}(l)\) and \(\mathrm{O}_{2}(g) ?\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.